Answer:
Step-by-step explanation:
Given: quadrilateral ABCD inscribed in a circle
To Prove:
1. ∠A and ∠C are supplementary.
2. ∠B and ∠D are supplementary.
Construction : Join AC and BD.
Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,
∠1=∠2-----(1)
∠3=∠4-----(2)
∠5=∠6-------(3)
∠7=∠8------(4)
Also, sum of angles of quadrilateral is 360°.
⇒∠A+∠B+∠C+∠D=360°
→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4
→→→2∠1+2∠4+2∠6+2∠8=360°
→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,
→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)
As, ∠A+∠B+∠C+∠D=360°
∠A+∠C+180°=360°
∠A+∠C=360°-180°------Using A
∠A+∠C=180°
Hence proved.
credit: someone else
Answer:
x = 9
Step-by-step explanation:
Since the figures are similar then the ratios of corresponding sides are equal, that is
= 
( cross- multiply )
12(x - 1) = 96 ( divide both sides by 12 )
x - 1 - 8 ( add 1 to both sides )
x = 9
Answer:
Hey there!
For the first question we use the triangle area formula: 1/2bh, or 1/2(8)(5). This gives us 20 for the area.
For the second question we get a trapezoid, since the cross section does not pass through the vertex.
Hope this helps :)
Answer:
here ya go
Step-by-step explanation:
1. 20
2.1793
3. 1943
im noy to sure on the bottom ones but use ctrl f in the notes you use for this or something and type in the "transacted" or something in the question and your answer should pop up
