There are 2 tangent lines that pass through the point
and
Explanation:
Given:
The point-slope form of the equation of a line tells us that the form of the tangent lines must be:
For the lines to be tangent to the curve, we must substitute the first derivative of the curve for :
Substitute equation [2] into equation [1]:
Because the line must touch the curve, we may substitute
Solve for x:
±
± <em> </em>
There are 2 tangent lines.
and
The answer to the problem would be false
7
You divide 28 by 4 and get 7. Then you divide 49 by whatever you get.
∠LQK+∠GQL=90º
Therefore:
(4n-15)+(3n)=90
7n=90+15
7n=105
n=105/7
n=15
∠LQK=4n-15=4(15)-15=60-15=45
Answer: ∠LQK=45º