Answer:
the area of a circle is
rsqr
32 x 32 =1024
Step-by-step explanation:
<h3>
Answer:</h3>
x = 1
<h3>
Step-by-step explanation:</h3>
<em>The only solution is an extraneous solution</em>, which is to say the equation has no solution.
The rational expression reduces to -1 (for x≠1), which makes the equation ...
1 = 1/x
The only solution to this is x=1, which is specifically disallowed.
___
If you subtract the right side, the equation becomes ...
((-x+1)(x) +2(x)(x -1) -(x -1))/(x -1) = 0
(-x^2 +x +2x^2 -2x -x +1)/(x -1) = 0 . . . . eliminate parentheses in the numerator
(x^2 -2x +1)/(x -1) = 0 . . . . . . . . . . . . . . . collect terms
(x -1)^2/(x -1) = 0 . . . . . . . . . . . . . . . . . . . factor
This is undefined for the only value of x that could possibly be a solution, x=1.
15, 30, 45, 60, 75, 90, 105, 120, 135, 150
20, 40, 60, 80, 100, 120, 140, 160, 180, 200
Smallest number would be 60 because it’s the least common number in both theaters.
Let me know if I’m right,
-Hoodie
Answer: x - int : (3,0)
Step-by-step explanation:
point-slope form: y - y1 = m(x - x1)
m = y2-y1/x2-x1
= -4-2/-3-6
=-6/-9
= 2/3
y1 = 2
x1 =6
y - 2 = 2/3(x-6)
x -int: when y = 0, what is x?
0-2 = 2/3(x-6)
-2 = 2/3x - 4
2 = 2/3x
x=3
~Hope this helps!~
13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0
Recall the double angle identity,
sin^2(x) = (1 - cos(2x))/2
If we let x = 13pi/12, then
sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]
where we took the negative square root because we expect a negative value.
Now, because cosine has a period of 2pi, we have
cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2
Then
sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]
sin(13pi/12) = - sqrt[2 - sqrt[3]]/2