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Sloan [31]
2 years ago
13

The tape diagram represents an equation.​

Mathematics
1 answer:
Lena [83]2 years ago
5 0

Answer:  w+1.3 = 2.7

Reason:

The smaller pieces (w and 1.3) combine to form the larger piece (2.7)

To find w, subtract 1.3 from both sides to get 1.4

1.4+1.3 = 2.7

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What is the distance between points P(8, 5) and Q(2,-3) to the nearest tenth?
Fantom [35]
I will say its the correct answer
4 0
3 years ago
In ΔKLM, k = 480 cm, ∠M=80° and ∠K=39°. Find the length of m
GuDViN [60]

Answer: 751

Step-by-step explanation:

6 0
3 years ago
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What is the sign of the product (–5)(–3)(–8)(–6)? Positive, because the products (–5)(–3) and (–8)(–6) are negative, and the pro
chubhunter [2.5K]

Answer:

The product (–5)(–3)(–8)(–6) should be Positive.

Step-by-step explanation:

The product of 2 negative numbers equal a positive product.

N * N = P

-5*-3=15

-8*-6=48

The product of 2 positive numbers is positive.

P * P = P

15 * 48 = 720

Your answer should be: Positive because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is positive.

6 0
3 years ago
Read 2 more answers
Select the correct location in the expression.
kogti [31]

Answer:

78

Correct term:60

Step-by-step explanation:

We are given that

\frac{4x^4-6x^3+6x+3}{x-3}

The quotient of this expression is given by

4x^3+6x^2+18x+78+\frac{183}{x-3}

We have to find the term in this expression  which contains an error.

\frac{4x^4-6x^3+6x+3}{x-3}

The quotient of this expression is given by

=4x^3+6x^2+18x+60

Dividend=Divisor\times quotient+ remainder

Using the formula

4x^4-6x^3+6x+3=(x-3)(4x^3+6x^2+18x+60)+\frac{183}{x-3}

We can see that in the given expression there is 60 in place of 78.

The error in the expression of quotient is 78.

Correct term is 60.

4 0
3 years ago
Describe the graph of the function f(x) = x3 − 11x2 + 36x − 36. Include the y-intercept, x-intercepts, and the end behavior.
jenyasd209 [6]
The function is f(x)=x^3-11x^2+36x-36.

To find the x-intercepts, we need to factorize the function. A very good idea is to first try the factors of 36:

f(1)=1-11+36-36, not 0

f(2)=8-44+72-36=-36+72-36=0. Here we have our first root (2).

Now we cad divide f(x) by (x-2) which will give us a quadratic expression, which we can factorize easily (if the discriminant is non negative).

We can also try some other factors of 36. Indeed we can check that 

f(3)=27-99+108-36=135-135=0, 
and
f(6)=216-396+216-36=0.

Thus, f(x)=(x-2)(x-3)(x-6). Note that if we expanded the right hand side expression, the constant term would be the product of the constants 2, 3, 6.

This is the reason why in the first place we looked at the factors of 36 for the possible zeros of f(x).


Thus, the x-intercepts are (2, 0), (3, 0), (6, 0), or 2, 3, 6. 

The y-intercept is f(0), which is -36.


Note that f(0)<f(2) because f(0)=-36 and f(2)=0. This means that at the left side, the graph is coming from - infinity. Similarly, 

we can check that f(10)=1000-1100+360-36=224> f(6). That is, to the right of our rightmost root, the graph is getting larger.

Thus, the end behaviors are: the graph goes to + infinity as x goes to + infinity, 

and it goes to minus infinity as x goes to - infinity.
7 0
3 years ago
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