Answer:
The probability of the event of identifying both the defective bulb in the second attempt is .
Step-by-step explanation:
The number of good light bulbs is 5 and the number of defective bulbs is 2.
It is provided that when a defective bulb is found in the inspection it is disposed.
If a defective bulb is found in the first trial the probability of his event is .
Now the remaining number of bulbs is 6.
If a defective bulb is found in the second trial the probability of his event is .
So the probability of identifying both the defective bulb in the second attempt is:
P (Selecting a defective bulb in 1st attempt) × P (Selecting a defective bulb in 2nd attempt) =
Thus, the probability of the event of identifying both the defective bulb in the second attempt is .