Five good light bulbs and two defective ones were mixed up unknowingly. To identify the defective ones for disposal, the bulbs a
1 answer:
Answer:
The probability of the event of identifying both the defective bulb in the second attempt is .
Step-by-step explanation:
The number of good light bulbs is 5 and the number of defective bulbs is 2.
It is provided that when a defective bulb is found in the inspection it is disposed.
If a defective bulb is found in the first trial the probability of his event is .
Now the remaining number of bulbs is 6.
If a defective bulb is found in the second trial the probability of his event is .
So the probability of identifying both the defective bulb in the second attempt is:
P (Selecting a defective bulb in 1st attempt) × P (Selecting a defective bulb in 2nd attempt) =
Thus, the probability of the event of identifying both the defective bulb in the second attempt is .
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Answer:
(b)
Step-by-step explanation:
1 male named Bart (b)
3 females named Charlene(c), Diana(d), and Erin(e).
Since there is replacement, the possible samples are:
bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.
Total Number of pairs = 16
Event of picking 2 males:bb
Event of 1 male:bc,cb,bd,db,be,eb
Event of picking 0 males:
cc, cd, ce, dc, dd, de, ec, ed, and ee.
b. The mean of the sampling distribution
c. No; the proportion of males is while the mean is
.
B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.