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iris [78.8K]
3 years ago
10

These are the answers that can be picked

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0
So what are we suppose to do?

Btw, i'm a poptart ^-^
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Find the equation in standard form of the line passing through the points (2,-3) and (4,2)
Sonja [21]

The equation of the line passing through the points (x_1,y_1) and (x_2,y_2) is

\frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1}. Here \frac{y_1-y_1}{x_2-x_1} is the slope of the line.

Substituting numerical values,

\frac{x-2}{y+3} =\frac{4-2}{2+3} \\ \frac{x-2}{y+3} =\frac{2}{5} \\ 5x-10=2y+6\\ 5x-2y-16=0

The equation of the line in standard form is 5x-2y-16=0.

5 0
4 years ago
Convert 14 ft in yd and ft
almond37 [142]

multiply 3 by 14 it equals 42...

hope this helpes...

3 0
3 years ago
The box plot below shows the total amount of time, in minutes, the students of a class surf the Internet every day:
VLD [36.1K]

Answer:

Step-by-step explanation:The box plot below shows the total amount of time, in minutes, the students of a class surf the Internet every day: Part A: List two pieces of information that are provided by the graph and one piece of information that is not provided by the graph. (4 points) Part B: Calculate the interquartile range of the data, and explain in a sentence or two what it represents.

6 0
3 years ago
The range of F(x) = logbx is the set of all positive real numbers.
shtirl [24]

Answer:

The range of F(x) = logbx is the set of all positive real numbers is TRUE

Step-by-step explanation:

Given:

A function which logarithmic i.e F(x)=logbX=logx/logb  with base 10

To Find;

Range belongs to All set are positive real numbers.

Solution:

The domain is function for which all set of inputs are defined  and range for function is that set of all output that functions takes.

So Simple logarithmic function y=logbX is

X=b^y

So  The functions has domain of all real values  and range set of all real number.

In general the function F(x) = logbx  where X>0 and b≠1  is continuous and one to one function.

logarithmic function is not defined for negative numbers or for zero.

And Also function approaches y-axis as x-tends to infinity but never touches the it.

Hence the Given statement is true

7 0
4 years ago
How do you solve this a^2+b^2=c^2
DiKsa [7]

Answer:

c = -\sqrt{a^2+b^2}

Step-by-step explanation:

-\sqrt{a^2+b^2=c}

7 0
4 years ago
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