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3 years ago

Could someone give me a hand

Mathematics

1 answer:

Minchanka [31]3 years ago

4 0

The answer is thirty two

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Evaluate the expression for the given value of the variable y/8+12;y=32

lisabon 2012 [21]

32÷8+12=16

32÷8=4

4+12=16

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3 years ago

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Find the unit rate <br><br> $28 for 7 people

Vlad1618 [11]

Answer: 4 dollars per person . that would be it .

Step-by-step explanation:

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3 years ago

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I NEED HELP!! pleaseee

Veronika [31]

Answer:

Step-by-step explanation:

line RPN = 180 = 4y - 10 + 90 + y

180 - 90 + 10= 5y

100 = 5y

y = 100/5

y = 20

4 0

2 years ago

3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall

Katen [24]

Answer:

The volume of the toy is $V=5.23\ ft^3$

Step-by-step explanation:

step 1

Find the volume of the hemisphere

The volume of the hemisphere is given by the formula

$V=\frac{2}{3}\pi r^{3}$

In this problem, the wide of the toy is equal to the diameter of the hemisphere

$D=2\ ft$

$r=2/2=1\ ft$ ----> the radius is half the diameter

substitute

$V=\frac{2}{3} \pi (1)^{3}=\frac{2}{3} \pi\ ft^3$

step 2

Find the volume of the cone

The volume of the cone is given by

$V=\frac{1}{3}\pi r^{2}h$

we know that

The radius of the cone is the same that the radius of the hemisphere

$r=1\ ft$

The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy

$h=4-1=3\ ft$

substitute the given values

$V=\frac{1}{3}\pi (1)^{2}(3)=\pi\ ft^3$

step 3

Find the volume of the toy

we know that

The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.

$V=(\frac{2}{3} \pi+\pi)\ ft^3$

$V=(\frac{5}{3}\pi)\ ft^3$

assume

$\pi=3.14$

$V=\frac{5}{3}(3.14)=5.23\ ft^3$

5 0

3 years ago

Plz help me I don’t get this

skelet666 [1.2K]

3/4 x 1/3 equals 1_12

6 0

3 years ago