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ivann1987 [24]
3 years ago
6

What is the value of the x variable in the solution to the following system of equations?

Mathematics
1 answer:
Dimas [21]3 years ago
7 0
The answer is 3. I hope this helps :))

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The unit rate 18 meters in 15 minutes
Zarrin [17]

Answer: 1.2 meters per min........

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can someone please help
Kitty [74]

Answer:

ez, all you need to do is find the area of the rectangle by itself so 3x9 is 27, cuz its formula is bxh then u need to find the area of the triangle so 3x3 which is 9 and divde by 2 which is 4.5 and 27-4.5 is 22.5 so thats ur answer.

Step-by-step explanation:

6 0
3 years ago
Find (f•g) (x) for the following functions.
Natasha2012 [34]

Answer:

D

Step-by-step explanation:

f(x) * g(x)= (3x^2-4x-5)(11x-3)

33x^3-44x^2-55x-9x^2+12x+15

33x^3-53x^2-43x+15

6 0
3 years ago
Trina planted plants in her garden last week. She planted twice as many cucumbers as zucchini and eight more tomatoes than cucum
maxonik [38]

Answer:

7 Zuchini, 14 Cucumbers and 22 Tomatoes plants.

Step-by-step explanation:

  • Let the number of tomatoes=t
  • Let the number of cucumber planted=c
  • Let the number of zucchini planted=z
  • Total Number of Plants=43

She planted twice as many cucumbers as zucchini, this is written as:

  • c=2z

She also planted eight more tomatoes than cucumbers, this is written as:

  • t=c+8=2z+8

In total, she planted 43 plants

Therefore:

z+(2z)+(2z+8)=43

5z+8=43

5z=43-8

5z=35

Divide both sides by 5

z=7

Number of Cucumbers, c=2z=2 X 7 =14

Number of Tomatoes, t=c+8=14+8=22

Therefore, she planted 7 Zuchini, 14 Cucumbers and 22 Tomatoes plants.

3 0
3 years ago
1^2 +2^2+••••+n^2=1/6n(n+1)(2n+1) <br>using maths induction ​
crimeas [40]

Hello,

if\ n=1\ then\ 1^2=1\ and\ \dfrac{1}{6}*1*2*3=1:\ true\ for\ n=1\\

We suppose the property true for n:

1²+2²+...+n²=n(n+1)(2n+1) / 6

and we are going to demonstrate that the property is true for n+1:

1²+2²+..+(n+1)²=(n+1)*(n+2)*(2n+3)/6

1^2+2^2+...+n^2+(n+1)^2\\\\=n*(n+1)*(2n+1)/6+(n+1)^2\\\\=(n+1)/6*[n(2n+1)+6n+6]\\\\=(n+1)/6*(2n^2+7n+6)\\\\=(n+1)(n+2)(2n+3)/6\\

5 0
3 years ago
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