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3 years ago

Please answer the questions before 12 am

Mathematics

1 answer:

Nesterboy [21]3 years ago

3 0

Answer:

Nope Nope

Step-by-step explanation:

Nevertheless

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Consider the equation y=-2x+5. Describe everything you know about this graph compared to the parent linear function y=x.

Mekhanik [1.2K]

Function y = -2x + 5:
slope of -2
y intercept at 5
x intercept at 2 1/2

function y = x
slope of 1
y intercept at 0
x intercept at 0

8 0

2 years ago

Suppose the polynomial f(x) has the following end behavior: as x approaches infinity, f(x) approaches infinity, and as x approac

galina1969 [7]

Answer:

C. x³+10x²−5x+5

E. 7x⁵+4x²

F. x+8

Step-by-step explanation:

The graph they described should look something like the one i drew below.

So all you have to do is look at the number with the highest exponent.

If the exponent is an odd number and the x is positive then that function will have an end behavior like the picture i posted.

x³ is good

-x³ is bad because of the negative sign

x² is bad because exponent is even

x⁷ is good

123x¹ is good

6 0

3 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

3 years ago

Use the number line to find the equivalent fraction

kifflom [539]

I think that the Equivalent fraction is 6/8

3 0

3 years ago

Read 2 more answers

A repairman leans the top of an 26 foot ladder against the

Natalija [7]

Answer:

26.42139285

Step-by-step explanation:

26x26 + 4.7x4.7 = c2

676 + 22.9 =c2

698.09=c2

square root of 698.09=26.42139285

26.42139285 = c

6 0

3 years ago