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Mandarinka [93]
3 years ago
6

What is the value of x in the equation 3x - 4y=65, when y=4?

Mathematics
1 answer:
grigory [225]3 years ago
7 0

Answer:

Step-by-step explanation:

Given 3x-4y=65

Y=4

So 3x-4×4=65

3x-16=65

3x=65+16

X=81/3

X=27

So value of X is 27

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A given line has the equation 10x + 2y = −2.
stepladder [879]
10x + 2y = -2

2y = -10x -2

y = -5x - 1 (slope is -5 and a parallel line will have the same slope)


y = mx + b

slope(m) = -5

12 = -5(0) + b

12 = 0 + b

12 = b

so the parallel line is y = -5x + 12

hope this helps, God bless!

3 0
3 years ago
Please help me I will crown
-Dominant- [34]

Answer:

B or D would be the best options for this question

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3 years ago
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Show work how you know it’s a function or not a function for each problem. PLEASE SOMEONE HELP ME OUT
Fudgin [204]

Answer: Function, not a function, Function, not a function

Step-by-step explanation:

For it to be a function, each value of x has to map onto one value of y.

  1. This is a function.
  2. Not a function since x=-1 has more than one y value.
  3. This is a function
  4. Not a function since x=-6 has more than one y value.
7 0
1 year ago
Compute the indicated derivative U(t) = 5.1t^2 − 1.7t; U'(6)
Nezavi [6.7K]

Answer: 59.5

Step-by-step explanation:

U(t) = 5.1t^2 − 1.7t

U'(t)=2*5.1t-1.7

U'(t)=10.2t-1.7

U'(6)=10.2(6)-1.7

U'(6)=61.2-1.7

U'(6)=59.5

6 0
1 year ago
Let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes. If the random var
jeka57 [31]

Answer:

The parameters of this exponential distribution is \lambda = \frac{1}{27} .

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes.

<u><em>So, X = time it takes for a person to choose a birthday gift</em></u>

The probability distribution function of exponential distribution is given by;

 f(x) = \lambda e^{-\lambda x}  , x >0      where, \lambda = parameter of distribution.

Now, the mean of exponential distribution is = \frac{1}{\lambda}  which is given to us as average value of 27 minutes that means  \lambda = \frac{1}{27} .

So, X ~ Exp( \lambda = \frac{1}{27} ) .

Therefore, the parameter of this exponential distribution is \lambda .

5 0
3 years ago
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