Picture is included ! help please !!

You make skateboard ramps by cutting pieces from a board that is 12 1/2 feet long.

Stels [109]

The length of the ramp is unknown.
If 6 ramps were cut from a board that is 12 1/2 feet long, the ramps would be about 2 feet long each which seems like a reasonable answer. The questions regarding how many boards are cut would need the length of the ramps. Lets say that the length is x. You can get 12 1/2 divided by x boards. In order to find out how much is left over, take the number of boards made, multiply it by how long they are. This product is then subracted from 12 1/2.

5 0

3 years ago

A bank with a branch located in a commercial district of a city has the business objective of developing an improved process for

tatiyna

Answer:

(a) The test statistic value is -4.123.

(b) The critical values of t are ± 2.052.

Step-by-step explanation:

In this case we need to determine whether there is evidence of a difference in the mean waiting time between the two branches.

The hypothesis can be defined as follows:

H₀: There is no difference in the mean waiting time between the two branches, i.e. μ₁ - μ₂ = 0.

Hₐ: There is a difference in the mean waiting time between the two branches, i.e. μ₁ - μ₂ ≠ 0.

The data collected for 15 randomly selected customers, from bank 1 is:

S = {4.21, 5.55, 3.02, 5.13, 4.77, 2.34, 3.54, 3.20, 4.50, 6.10, 0.38, 5.12, 6.46, 6.19, 3.79}

Compute the sample mean and sample standard deviation for Bank 1 as follows:

$\bar x_{1}=\frac{1}{n_{1}}\sum X_{1}=\frac{1}{15}[4.21+5.55+...+3.79]=4.29$

$s_{1}=\sqrt{\frac{1}{n_{1}-1}\sum (X_{1}-\bar x_{1})^{2}}\\=\sqrt{\frac{1}{15-1}[(4.21-4.29)^{2}+(5.55-4.29)^{2}+...+(3.79-4.29)^{2}]}\\=1.64$

The data collected for 15 randomly selected customers, from bank 2 is:

S = {9.66 , 5.90 , 8.02 , 5.79 , 8.73 , 3.82 , 8.01 , 8.35 , 10.49 , 6.68 , 5.64 , 4.08 , 6.17 , 9.91 , 5.47}

Compute the sample mean and sample standard deviation for Bank 2 as follows:

$\bar x_{2}=\frac{1}{n_{2}}\sum X_{2}=\frac{1}{15}[9.66+5.90+...+5.47]=7.11$

$s_{2}=\sqrt{\frac{1}{n_{2}-1}\sum (X_{2}-\bar x_{2})^{2}}\\=\sqrt{\frac{1}{15-1}[(9.66-7.11)^{2}+(5.90-7.11)^{2}+...+(5.47-7.11)^{2}]}\\=2.08$

(a)

It is provided that the population variances are not equal. And since the value of population variances are not provided we will use a t-test for two means.

Compute the test statistic value as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}}$

$=\frac{4.29-7.11}{\sqrt{\frac{1.64^{2}}{15}+\frac{2.08^{2}}{15}}}$

$=-4.123$

Thus, the test statistic value is -4.123.

(b)

The degrees of freedom of the test is:

$m=\frac{[\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}]^{2}}{\frac{(\frac{s_{1}^{2}}{n_{1}})^{2}}{n_{1}-1}+\frac{(\frac{s_{2}^{2}}{n_{2}})^{2}}{n_{2}-1}}$

$=\frac{[\frac{1.64^{2}}{15}+\frac{2.08^{2}}{15}]^{2}}{\frac{(\frac{1.64^{2}}{15})^{2}}{15-1}+\frac{(\frac{2.08^{2}}{15})^{2}}{15-1}}$

$=26.55\\\approx 27$

Compute the critical value for α = 0.05 as follows:

$t_{\alpha/2, m}=t_{0.025, 27}=\pm2.052$

*Use a t-table for the values.

Thus, the critical values of t are ± 2.052.

3 0

3 years ago

which of the following is the most appropriate unit to describe the rate at which people are entering a theme park A. hours per

Aleksandr-060686 [28]

People per hour because the dependent quantity is the hours.
The number of people that enter depends on the number of hours the park is open

7 0

3 years ago

Read 2 more answers

Please help. Correct answer will get brainliest and full ratings.

irina1246 [14]

Hope this helps but I think the answer is A.To find this look at the points on the graph and find out what their ordered pairs are. Once you do that look at the x values for all the ordered pairs.Example the x value for the ordered pair (-3,-1) is -3.After you have found all the x values put them in order from least to greatest.I any x values are repeated then leave them out.Example if your x values are 0,1,1,2,3,3,4 then leave the extra 1 and 3 out and then you have 0,1,2,3,4.Once you have put the x values in order from least to greatest and left out any extra repeated x values the you are done and you have your domain for the function.

5 0

3 years ago

F(x)=(x+1)(x+3)(x−4 the standard form of F(x)

olga55 [171]

Answer:

f(x)=x^3-13x-12

Step-by-step explanation:

4 0

3 years ago