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iVinArrow [24]
4 years ago
10

How do you do this? Thanks for your time and effort!

Mathematics
1 answer:
V125BC [204]4 years ago
3 0
Well first you have to simplify the denominators with x, by multiplying the denominator on the left times the top and bottom of the middle, and vice versa to get 10x/(4x^2-4x)-9(2x-2)/(4x^2-4x)=-1/4 and then you combine the fractions on the left to get 2(9-4x)/(4x^2-4x)=-1/4 and then you cross multiply the fractions to get 8(9-4x)=-4x^2+4x and then simplify to get 72-32x=-4x^2+4x and then 4x^2-36x+72=0 which then we can turn into 4(x-6)(x-3)=0 so x is 6 and 3
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The degree of polynomial is ?
seropon [69]
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6 0
2 years ago
Pencils are sold in packages of 10 and erasers are sold in packages 6 what is the least number of pencils and erasers you can bu
algol [13]
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3 0
3 years ago
How do I solve this?
Serhud [2]

Answer:

44.94

Step-by-step explanation:

Use trigonometric ratios to find the unknown side.

Since you are given the adjacent side and the opposite side is in question, use the tangent ratio.

tan(x) = opposite/adjacent

Replace the variables with given values.

tan(59) = x/27

Isolate the variable.

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Use a calculator to evaluate the answer.

x = 27tan(59) ≈ 44.94

Please mark as Brainliest! :)

8 0
4 years ago
Simplify (Are all division)<br><br>2+4i<br>3i<br><br>3+2i<br>4+i<br><br>2i^11
Alla [95]

We\ know:\ i=\sqrt{-1}\to i^2=-1

\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i

\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i

2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i


Used:\ (a+b)(a-b)=a^2-b^2

6 0
3 years ago
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Ghella [55]
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