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abruzzese [7]
3 years ago
9

What is the sum of 7 and t/2

Mathematics
2 answers:
tekilochka [14]3 years ago
6 0

Answer:

14/2+t/2 so ( 14+t)/2 is the answer

o-na [289]3 years ago
6 0
7+(t/2) =
(7)(2)+(t)(1) /(2) (1)
=(14+t)/(3)
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A 70-foot wire attached to the top of a building is anchored to the ground 20 feet from the base of the building. Which value is
JulijaS [17]

Answer:

The the angle which the wire make with the ground is 1.280 radian .

Step-by-step explanation:

Given as :

The length of the wire attached to the top of building = OB = 70 foot

The distance of wire anchored from base of ground = OA = 20 feet

Let the angle made by wire en and ground = Ф

Now from ,  In Triangle AOB

Cos angle = \dfrac{\textrm Base}{\textrm Hypotenuse}

Or, Cos Ф =  \dfrac{\textrm OA}{\textrm OB}

or, Cos Ф =  \dfrac{\textrm 20}{\textrm 70}

Or, Cos Ф =  \dfrac{\textrm 2}{\textrm 7}

∴  Ф = Cos^{-1}(\frac{2}{7})

I.e Ф = 73.39°

Now in radian ,

∵ 180° = \pi radian

∴ 73.39° = \frac{\pi }{180} × 73.39°

             =  \frac{3.14 }{180} × 73.39° = 1.280 radian

Hence The the angle which the wire make with the ground is 1.280 radian . Answer

4 0
3 years ago
Read 2 more answers
the area of a square whose sides have length x cm is increasing at the rate of 12cm²/s. how fast is the length of a side increas
katovenus [111]

Answer:

0.67 cm/s

Step-by-step explanation:

The area of a square is given by :

A=x^2 ....(1)

Where

x is the side of a square

\dfrac{dA}{dt}=12\ cm^2/s

Differentiating equation (1) wrt t.

\dfrac{dA}{dt}=2x\times \dfrac{dx}{dt}

When A = 81cm²​, the side of the square, x = 9 cm

Put all the values,

12=2\times 9\times \dfrac{dx}{dt}\\\\\dfrac{dx}{dt}=\dfrac{2}{3}\\\\\dfrac{dx}{dt}=0.67\ cm/s

So, the length of the side of a square is changing at the rate of 0.67 cm/s.

4 0
2 years ago
30 POINTS,NEED HELP ASAP !!!
zaharov [31]

Answer: OPTION A.

Step-by-step explanation:

You can observe that in the figure CDEF the vertices are:

C(-2,-1),\ D(-2,0),\ E(2,2)\ and\ F(2,1)

And in the figure C'D'E'F'  the vertices are:

C'(-8,-4),\ D'(-8,0),\ E'(8,8)\ and\ F'(8,4)

For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:

For C'(-8,-4) and C(-2,-1):

\frac{-8}{-2}=4\\\\\frac{-4}{-1}=4

Let's choose another vertex. For E'(8,8) and E(2,2):

\frac{8}{2}=4\\\\\frac{8}{2}=4

You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.

Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:

(x, y)→(4x, 4y)

7 0
3 years ago
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What is 60/d when d=10
erastova [34]
It is 6 60 divided by 10 is 6
3 0
3 years ago
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How do I simplify the expression 7^0+7^2 over (7^3)^2
AlekseyPX

\frac{7^0+7^2}{(7^3)^2}=\frac{1+49}{7^6} = \frac{50}{117649}

Ok done. Thank to me :>

7 0
2 years ago
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