Does anyone know this?
1 answer:
You might be interested in
we are given
now, we can compare it with
we can find b
we get
now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8
b=1.6
b=1.4
b=1.2
now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
Answer:
f(x) = + 2x³ - 4x² - 6x + 3
Step-by-step explanation:
Note that radical zeros occur in conjugate pairs, thus
- 1 + is a zero then - 1 -
is also a zero
is a zero then -
is also a zero
Thus the corresponding factors are
(x - (- 1 + ) ), (x - (- 1 -
) ), (x -
), (x - (-
)), that is
(x + 1 - ), (x + 1 +
), (x -
), (x +
)
The polynomial is then the product of the roots
f(x) = (x + 1 - )(x + 1 +
)(x -
)(x +
)
= ((x + 1)² - ()²)((x² - (
)²)
= (x² + 2x + 1 - 2)(x² - 3)
= (x² + 2x - 1)(x² - 3) ← distribute
= - 3x² + 2x³ - 6x - x² + 3
= + 2x³ - 4x² - 6x + 3