A square piece of fabric has sides length 3.7 cm what’s the area?

it costs $20 for 4 play tickets and $35 for 7 play tickets. Is cost per ticket constant? why or why not?

KonstantinChe [14]

Answer:

The cost per ticket is<u> constant</u>.

Step-by-step explanation:

Given:

It costs $20 for 4 play tickets and $35 for 7 play tickets.

Now, to get whether cost per ticket is constant or not.

So, if the cost per ticket is constant that means the cost of ticket for a play or more is fixed, non-varying and it does not change.

Now, we check it:

4 play tickets costs = $20.

1 play tickets costs = $20 ÷ 4 = $5.

So, 7 play tickets costs = $5 × 7 = $35.

Thus, the cost of ticket for play is not changing and it is constant.

So the cost per ticket is constant.

Therefore, the cost per ticket is constant.

4 0

3 years ago

Help me please i have no idea. NO GUESSING

Diano4ka-milaya [45]

The answer for this equation full simplify is (D.)

3 0

3 years ago

Read 2 more answers

In a survey, 11 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped

pickupchik [31]

Answer:

The population standard deviation is not known.

90% Confidence interval by T₁₀-distribution: (38.3, 53.7).

Step-by-step explanation:

The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus $11 - 1 = 10$ .

Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,

The area to the left of the lower end of the interval shall be $1/2 \cdot (1 - 0.90)= 0.05$ .
The area to the left of the upper end of the interval shall be $0.05 + 0.90 = 0.95$ .

Look up the t-score of the upper end on an inverse t-table. Focus on the entry with

a degree of freedom of 10, and
a cumulative probability of 0.95.

$t \approx 1.812$ .

This value can also be found with technology.

The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:

$\displaystyle t \cdot \frac{s_{n-1}}{\sqrt{n}}$ ,

where

$t$ is the t-score at the upper end of the interval,
$s_{n-1}$ is the unbiased estimate for the standard deviation, and
$n$ is the sample size.

For this confidence interval:

$t \approx 1.812$ ,
$s_{n-1} = 14$ , and
$n = 11$ .

Hence the width of the 90% confidence interval is

$\displaystyle 1.812 \times \frac{14}{\sqrt{10}} \approx 7.65$ .

The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:

$(38.3, 53.7)$ .

5 0

3 years ago

Aubree invested $8,300 in an account paying an interest rate of 2.2% compounded quarterly. Assuming no deposits or withdrawals a

Triss [41]

Answer:

$25,735.03

Step-by-step explanation:

I plugged your numbers into the really big formula

7 0

3 years ago

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Which is the graph of f(x)=2(3)^x

likoan [24]

Let's plug the values and see which couple satisfy the equation: since $y = 2\cdot 3^x$ , if we plug the values from the first option $(x,y)=(1,6)$ we have