Answer:
public class Main
{
public static void printString(String strText, int intNumber) {
for(int i=0; i<intNumber; i++){
System.out.println(strText);
}
}
public static void main(String[] args) {
printString("Brainly", 3);
}
}
Explanation:
- Define a function called <em>printString</em> that takes two parameters - a String and an int. Since the function will print out the given String, it's type will be <u>void</u>.
- Use <em>for loop</em> to iterate according to the given number and print the given string
- In the main, call the <em>printString </em>function with some parameters.
import java.util.Scanner;
public class JavaApplication58 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a positive integer:");
String num = scan.nextLine();
for (int i = num.length()-1; i >=0; i--){
System.out.println(num.charAt(i));
}
}
}
I hope this helps!
Answer:
Answer is A. One.
Refer below.
Explanation:
A data flow cannot go directly back to the same process it leaves. There must be at least one other process that handle(s) the data flow, produce(s) some other data flow, and return(s) the original data flow to the beginning process.
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