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3 years ago

How to write four million

Mathematics

1 answer:

Furkat [3]3 years ago

6 0

4,000,000

hope this helps

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The work of a student to find the dimensions of a rectangle of area 8 + 16x and width 4 is shown below:

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3 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

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2 years ago

(5ab-4a-6)-(4ab-1) find the sum please fast

jekas [21]

We need to get rid of expression parentheses.

If there is a negative sign in front of it,

each term within the expression changes sign.

Otherwise, the expression remains unchanged.

Numerical 'like' terms will be added. There is only one group of like terms

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3 years ago

Which is The graph of f(x) = 5(2)^x

Snezhnost [94]

The graph reflecting the mathematical equation f(x) = 5*2^x is attached on this answer. Graph shows the exponential manner with the y-intercept is at y = 5. we can plot this graph by substituting points of x from a certain range (positive and negative) and get their corresponding y's

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3 years ago

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67 to the 2nd power, plz tell me if the answer is a prime number<br><br> Who wants to t a l k

Galina-37 [17]

Answer:

No, it is not prime.

Step-by-step explanation:

67^2 = 4489

A number cannot be prime if it is divisible by a number besides 1 and itself. 4489 is divisible by 67; no perfect square can be prime.

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2 years ago