Draw a triangle with shortest side on the ground (horiz.). The length of this side is 80 feet. Two angles touch the ground: a right angle, and the 70 degree angle.
Then the height of the building is the 2nd shortest side.
The tangent function is the appropriate one to use here:
opp h
tan 70 deg = -------- = ----------
adj 80 ft
h
Since tan 70 deg = 2.75, 2.75 = -------
80 ft
so h = building height = (80 ft)(2.75) = 219.8 ft
Answer:
when 0 on the bottom is zero
Step-by-step explanation:
that mean there would be no whole nor a proper quotient
Answer:
379.56ft²
Step-by-step explanation:
Oh lordy why, okay we got this:
So we're going to start with the area of the square, this is easy because all of the sides are 25ft, so we just have to plug into our formula for squares (base x height):
25 x 25 = 625
Now we have to do the semicircle, remember that the formula for the area of a circle is pi x radius², we're using 3.14 for pi, so we have to find the radius (half the diameter):
25 ÷ 2 = 12.5
12.5² = 156.25
3.14 x 156.25 = 490.625
Normally we would stop here, but because this is only a semicircle, we have to divide by two:
490.625 ÷ 2 = 245.3125
So, now that we have our two areas, we have to subtract the semicircle from the square:
625 - 245.3125 = 379.6875
Now, I realize that his answer isn't in your cute little word bank, but that because I rounded pi, so the closest is 379.56
So, the area of the figure is 379.56ft²
if this is wrong let me know so I can fix it
hope this helps:)
For a better understanding of the solution given here please find the attached file which has the relevant diagram.
To answer this question we will have to make use of <u>the Isosceles Triangle Theorem</u> which states that the perpendicular bisector of the base of an isosceles triangle is also the angle bisector of the vertex angle. Thus, as a corollary we know that is EF is the angle bisector of the vertex angle ∠E, then, EF is the perpendicular bisector of the of the base DK.
Please follow the diagram of a complete understanding of the logic and the solution.
As EF is the angle bisector as given in the question, thus we will have:
.
Also, from the Theorem we know that KF will be half of DK and thus, KF will be:
centimeters.
Likewise, from the same theorem we have: 
