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AVprozaik [17]
3 years ago
5

19. Which is the suitable identity used to evaluate 9992 ?

Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

I suppose you mean 999^2

(1000-1)^2

which comes under the identity

(a-b)^2=

(a^2 + b^2 - 2ab)

hope this helps

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Assume Cylinder A and Cone B are the same height and the bases have the same radius. If A has a volume of 18π cm3, what is the v
disa [49]

Answer:

Option A  V_B=19\ cm^3

Step-by-step explanation:

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V_B = \pi\frac{hr ^ 2}{3}

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V_A = \pi(r ^ 2)h

Both figures have the same height h and the same radius r.

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8 0
3 years ago
Read 2 more answers
The solution set for <br> 6a^2-a-5=0
Alex_Xolod [135]

Answer:

a=1 or a=5/6

Step-by-step explanation:

I'm going to attempt to factor 6a^2-a-5

a=6

b=-1

c=-5

Find two numbers that multiply to be a*c and add to be b.

a*c=-30                                   =-6(5)

b=-1                                          =-6+5

So replace -a with -6a+5a in the expression we started with

6a^2-6a+5a-5

now we factor by grouping

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(a-1)(6a-5)

Now let's solve the equation:

(a-1)(6a-5)=0

So a=1 or a=5/6

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3 years ago
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2 years ago
$1400 principal annual earning 6% compound semiannually, after 10 years
shusha [124]
The formula to use is:
A=P(1+r/n)^nt
Plug in the values:
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Make sense?
3 0
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