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Salsk061 [2.6K]
4 years ago
15

Read the following scenario:

Computers and Technology
1 answer:
Zigmanuir [339]4 years ago
7 0
The answer would be option C "The app company will sue the multimedia artist for breach of contract." The company bought the game therefore it's no longer his and the multimedia artist cannot release the original version because the app is no longer his and he will be sued for breach of contract. Because if the popular company bought the app from the <span>multimedia artist they would have to sign a contract and other paper work to confirm their purchase.

Hope this help!
</span>
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cout &lt;&lt; "Part 1" &lt;&lt; endl; // Part 1 // Enter the statement to print the numbers in index 4 and index 9 // put a spac
Margarita [4]

Answer and Explanation:

#include <iostream>

using namespace std;

int printEven(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2==0)

{

count++;

cout<<array[i]<<" ";

}

}

return count;

}

void printAll(int array[],int n)

{

for(int i=0;i<n;i++)

{

cout<<array[i]<<" ";

}

}

int computeTotalOdds(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2!=0)

{

count++;

 

}

}

return count;

}

int main()

{

int array1[20] = {3, 18, 1, 25, 4, 7, 30, 9, 80, 16, 17};

int numElements = 11;

cout << "Part 1" << endl;

cout<<array1[4]<<" "<<array1[9];

cout << endl;

cout<<array1[0]<<" "<<array1[8];

cout << endl;

array1[2]=12;

cout << "\nPart 2" << endl;

printAll(array1,numElements);

 

cout << "\nPart 3" << endl;

int evens;

evens=printEven(array1,numElements);

 

 

 

 

// This will print the number of evens in the array.

cout << endl << evens;

 

cout << "\nPart 4" << endl;

 

int total;

 

total=computeTotalOdds(array1,numElements);

cout << endl << total;

 

return 0;

}

3 0
3 years ago
Javier develops sophisticated fashion websites. He has been asked by the owner of a leading fashion brand to create web content
saul85 [17]

Answer:

hyperlinks

Explanation:

Javier should use hyperlinks to show the users the possible choices for their clothing.  This is really a terrible question and not likely in any real world scenario.  Fashion is always forward thinking and on the cutting edge.  When was the last time you went to a fashion website and were left with only choices to click on a hyperlink?  As Tim Gun would say "Make it work."  If I were able I would include a hyperlink using the previous sentence as the clickable link with a URL reference to

https : //en.wikipedia.org/wiki/Tim_Gunn (spaces after https to make this link not get censored)

to illustrate the way to show that hyperlinks have no real application on modern fashion website.  But they would have great utility here inside the answers section.  But they also are cause for a securtity concern and may be killed by the moderators

7 0
3 years ago
What does "ttyt" stand for?
EastWind [94]
TTYT stands for "talk to you tomorrow".
6 0
4 years ago
Read 2 more answers
Write a program to implement problem statement below; provide the menu for input N and number of experiment M to calculate avera
zalisa [80]

Answer:

Explanation:

#include<iostream>

#include<ctime>

#include<bits/stdc++.h>

using namespace std;

double calculate(double arr[], int l)

{

double avg=0.0;

int x;

for(x=0;x<l;x++)

{

avg+=arr[x];

}

avg/=l;

return avg;

}

int biggest(int arr[], int n)

{

int x,idx,big=-1;

for(x=0;x<n;x++)

{

if(arr[x]>big)

{

big=arr[x];

idx=x;

}

}

return idx;

}

int main()

{

vector<pair<int,double> >result;

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

int choice;

cin>>choice;

while(choice!=2)

{

int n,m;

cout<<"Enter N"<<endl;

cin>>n;

cout<<"Enter M"<<endl;

cin>>m;

int c=m;

double running_time[c];

while(c>0)

{

int arr[n];

int x;

for(x=0;x<n;x++)

{

arr[x] = rand();

}

clock_t start = clock();

int pos = biggest(arr,n);

clock_t t_end = clock();

c--;

running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;

}

double avg_running_time = calculate(running_time,m);

result.push_back(make_pair(n,avg_running_time));

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

cin>>choice;

}

for(int x=0;x<result.size();x++)

{

cout<<result[x].first<<" "<<result[x].second<<endl;

}

}

8 0
3 years ago
What type of storage drive contains multiple spinning platters?
Gala2k [10]

The type of storage drive that contains multiple spinning platters is called; Hard disk drives

<h3>What is the hard disk drive?</h3>

A computer hard disk drive (HDD) is a non-volatile data storage device. Non-volatile refers to storage devices that maintain stored data when turned off.

Now, the correct answer to the question is hard disk drives. This is because a hard disk drive is comprised of a stack of spinning metal disks known as platters. Each spinning disk has trillions of tiny fragments that could possibly be magnetized in order to represent bits (1s and 0s in binary code).

Read more about Hard disk drives at; brainly.com/question/24498473

#SPJ12

8 0
2 years ago
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