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Lunna [17]
3 years ago
13

Lesson 1 (4.0 points)

Computers and Technology
2 answers:
sesenic [268]3 years ago
8 0


3. Hold down the CTRL, ALT, and DELETE keys simultaneously, click Task Manager option, then right-click the frozen program's name, and finally click the end task button.


KATRIN_1 [288]3 years ago
6 0

1. What is code?

text that is written in a human-readable programming language that a computer can also interpret.

2. What does the Python(command line) interpreter’s command prompt look like? (0.5 points)

It looks like this: >>>

3. Name at least one way to deal with a frozen window. (0.5 points)

If the Python (command line) window freezes, select the  

Close button to force the window to close, and then reopen the window and repeat any steps that were lost.

4. What does the reset() command do? (1.0 points)

erases everything drawn by the turtle and moves the turtle back to its starting position.

5. What is an argument? (1.0 points)

 a letter, number, word, or combination of those that a command needs in order to work.

Lesson 2

1. What is the radius of a circle? (1.0 points)

is the distance from the center of the circle to the line of the circle. The larger the radius, the larger the circle drawn by the turtle will be.

2. In the circle() command, what is the steps argument? (1.0 points)

If the circle() command has a positive number argument, the turtle will draw a circle moving forward counterclockwise from its starting place.

3.In the forward() command, what does the number argument inside the parentheses do? (1.0 points)  (NOT 100% sure about this one but was on the same line in content and said same thing so went with it ^w^)

This number describes the radius of the circle that should be drawn.

all ive got for now

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Answer:

Check the explanation

Explanation:

#include <iostream>

using namespace std;

void hex2dec(string hex_num){

int n = 0;

//Loop through all characters in string

for(int i=0;i<hex_num.size();i++){

//take ith character

char c = hex_num[i];

//Check if c is digit

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n = 16*n + (c-48);

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cout<<hex_num<<" : "<<n<<endl;

}

int main()

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hex2dec("EF10");

hex2dec("AA");

return 0;

}

The Output can be seen below :

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Read 2 more answers
Convert infix to postfix
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Answer:

static int checkSymbol(char ch)

{

switch (ch)

{

case '+':

case '-':

return 1;

case '*':

case '/':

return 2;

case '^':

return 3;

}

return -1;

}

static String convertInfixToPostfix(String expression)

{

String calculation = new String("");

Stack<Character> operands = new Stack<>();

Stack<Character> operators = new Stack<>();

 

for (int i = 0; i<expression.length(); ++i)

{

char c = expression.charAt(i);

if (Character.isLetterOrDigit(c))

operands.push(c);

else if (c == '(')

operators.push(c);

 

else if (c == ')')

{

while (!operators.isEmpty() && operators.peek() != '(')

operands.push(operators.pop());

 

if (!operators.isEmpty() && operators.peek() != '(')

return NULL;    

else

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}

else

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while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))

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}

while (!operators.isEmpty())

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while (!operands.isEmpty())

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calculation=calculation.reverse();

return calculation;

}

Explanation:

  • Create the checkSymbol function to see what symbol is being passed to the stack.
  • Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
  • Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
  • While the operators is  not empty, keep pushing the character to the operators stack.
  • At last reverse and return the calculation which has all the results.
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