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Annette [7]
3 years ago
13

g A 5 foot tall man walks at 10 ft/s toward a street light that is 20 ft above the ground. What is the rate of change of the len

gth of his shadow when he is 25 ft from the street light

Mathematics
1 answer:
vredina [299]3 years ago
7 0

Answer:

-\frac{10}{3}ft/s

Step-by-step explanation:

We are given that

Height of man=5 foot

\frac{dy}{dt}=-10ft/s

Height of street light=20ft

We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.

ABE and CDE are similar triangle because all right triangles are similar.

\frac{20}{5}=\frac{x+y}{x}

4=\frac{x+y}{x}

4x=x+y

4x-x=y

3x=y

3\frac{dx}{dt}=\frac{dy}{dt}

\frac{dx}{dt}=\frac{1}{3}(-10)=-\frac{10}{3}ft/s=-\frac{10}{3}ft/s

Hence, the rate of change of the length of his shadow when he is 25 ft from the street light=-\frac{10}{3}ft/s

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ABCD is a square. M is the midpoint of BC and N is the midpoint of CD. A point is selected at random in the square. Calculate th
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1/8 or 0.125

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3 years ago
Evaluate the principal square root of 64
anygoal [31]
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3 0
3 years ago
Read 2 more answers
Lisa spends 1/5 of an hour doing her math homework and 1/3 of an hour doing her social studies homework. What fraction of an hou
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To solve this, all you have to do is add 1/5 and 1/3.
Well, you might be thinking, "But the denominators are not the same! Fractions have to have like denominators in order to be added together!" And you are right. So, all we have to do, is make them both have the same denominator. To do this, we have to multiply both the numerator and denominator by the same number to find an equivalent fraction.
For 1/5, we can multiply both the numerator and denominator by 3, to get 3/15. 
Likewise, we can multiply both the numerator and denominator of 1/3 by 5, to get 5/15.
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3/15+5/15=8/15, so she spends 8/15 hour on her math and social studies homework.
Hope I helped!
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3 years ago
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