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Reptile [31]
3 years ago
7

Find the value of x and y

Mathematics
1 answer:
Goryan [66]3 years ago
7 0

Answer:

x=  9     y=5

Step-by-step explanation:

hello :

use phtagor-rul :

y² = 3²+4²

y² =25

so : y=5

same method :

15²=12²+x²

x² =15²-12²

x² =225-144

x² = 81

so : x= 9

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Claire Judice
Julli [10]

Answer:

The values of 'x' are -1.2, 0, 0, -4i or 4i.

Step-by-step explanation:

Given:

The equation to solve is given as:

5x^5+6x^4+80x^3+96x^2=0

Factoring x^2 from all the terms, we get:

x^2(5x^3+6x^2+80x+96)=0

Now, rearranging the terms, we get:

x^2(5x^3+80x+6x^2+96)=0

Now, factoring 5x from the first two terms and 6 from the last two terms, we get:

x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0

Now, equating each factor to 0 and solving for 'x', we get:

x^2=0\\x=0\ and\ 0\\\\5x+6=0\\x=\frac{-6}{5}=1.2\\\\x^2+16=0\\x^2=-16\\x=\sqrt{-16}=\pm 4i

There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.

Therefore, the values of 'x' are -1.2, 0, 0, -4i or 4i.

4 0
4 years ago
Which of the following is a pair of vertical angles? <br><br> EXAMPLE: 1 and 4 , 1 and 5
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Answer:

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Step-by-step explanation:

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