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3 years ago

Help please?

Mathematics

1 answer:

ziro4ka [17]3 years ago

8 0

Answer:

cos(θ) = -1/2
tan(θ) = √3

Step-by-step explanation:

You know that ...

cos(θ)² = 1 - sin(θ)²
tan(θ) = sin(θ)/cos(θ)
cosine is negative in the third quadrant (where π < θ < 3π/2)

Using what you know about the relationships of these trig functions, you can find ...

cos(θ)² = 1 - ((-√3)/2)² = 1 - 3/4 = 1/4

cos(θ) = -1/2 . . . . . negative square root of 1/4

tan(θ) = sin(θ)/cos(θ) = ((-√3)/2)/(-1/2)

tan(θ) = √3

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