W = L - 7
WL = 78
(L-7)L = 78
L^2 - 7L - 78 = 0
Factorize: (L-13)(L+6) = 0
L = 13 or -6
A length cannot be negative, so the length must be 13 miles.
The width is 13-7 = 6 miles.
Answer:
A) R = P/I²
Step-by-step explanation:
I = √P/R
Square each side
I^2 = (√P/R)^2
I^2 = P/R
Multiply each side by R
I^2R =P/R * R
I^2R = P
Divide by I^2
I^2R / I^2 = P/ I^2
R = P/ I^2
Hello there! You can do something like this:
Kelly has 3/4 cup of a bottle of water. She likes to drink 5 times the amount of that every day. How many cups of water does Kelly like to drink every day?
Hope this helped you!
Good luck!
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span> =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).
Answer: 48
Step-by-step explanation:
