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Neporo4naja [7]
3 years ago
12

Round each number to the nearest tenth. What is the best estimate for the answer to 382.24 – 297.28?

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
8 0
When rounded off then it comes
382.2-297.3=84.9
musickatia [10]3 years ago
4 0
382.2-297.3=84.9
How i rounded ... 382.24 (0-4 we round it on the same decimal for ex. 2 as we had in this problem.In the another one we have 297.28 (5-9 we round it on the bigger decimal for ex. 3 as we had in this problem.)Hope this helped.
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Samia created the following tables of values for a linear system. She concluded that there is no
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Step-by-step explanation:

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Write an equation in slope-intercept form for each of these representations.
PtichkaEL [24]

Answer:

1.     y= -1/4x +2

2.    y= -2x -1

Step-by-step explanation:

7 0
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Write an equation in slope-intercept form for the line that passes through the point (-8, 2) and is perpendicular to the line y
tamaranim1 [39]

Answer:

y = -5x/4 - 8

Step-by-step explanation:

Two lines that are perpendicular have slopes that are opposite reciprocals.

Since the slope of the given line is 4/5, the opposite reciprocal of that is -5/4. So the equation has a slope of -5/4.

Since we know the coordinate of a point of the other equation, we can plug that into the point-slope form equation y - y1 = m(x - x1):

y - 2 = -5/4(x-(-8))

Simplify:

y - 2 = -5/4(x+8)

y - 2 = -5x/4 - 10

So the equation in slope-intercept form is:

y = -5x/4 - 8

3 0
3 years ago
A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled
klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5

The standard deviation of the sample is calculated as:

s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8

Then, we can calculate the standard error of the mean as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5

6 0
3 years ago
Please help me!
Zigmanuir [339]

Answer:

s = 14

Step-by-step explanation:

Step 1: Combine like terms.

  • (\frac{2}{3}s + \frac{5}{6}s) = 21
  • (\frac{4}{6}s + \frac{5}{6}s) = 21
  • \frac{9}{6}s = 21
  • \frac{3}{2}s=21

Step 2: Multiply both sides by 2/3.

  • \frac{3}{2}s * \frac{2}{3} = 21 * \frac{2}{3}
  • s = \frac{42}{3}
  • s = 14
8 0
2 years ago
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