1 A phosphate
1 answer:
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Answer:
B) 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1 orange eyes, green skin, two eyes : 1 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye
Explanation:
Parentals: BbGgCc x bbggcc
The punette square diagram of the cross of these two parents is attached.
B = black eyes, b = orange eyes;
G = green skin, g = white skin;
C = two eyes, c = one eye
Progeny with BbGgCc genotype → black eyes, green skin, two eyes = 8
Progeny with BbGgcc genotype → black eyes, green skin, one eye = 8
Progeny with BbggCc genotype → black eyes, white skin, two eyes = 8
Progeny with bbGgCc genotype → orange eyes, green skin, two eyes = 8
Progeny with Bbggcc genotype → black eyes, white skin, one eye = 8
Progeny with bbGgcc genotype → orange eyes, green skin, one eye = 8
Progeny with bbggCc genotype → orange eyes, white skin, two eyes = 8
Progeny with bbggcc genotype → orange eyes, white skin, one eye = 8
So, if we will see them in the form of ratio then each of the genotype will be in the ratio of 1 i.e. black eyes, green skin, two eyes: black eyes, green skin, one eye: black eyes, white skin, two eyes: orange eyes, green skin, two eyes: black eyes, white skin, one eye: orange eyes, green skin, one eye: orange eyes, white skin, two eyes : orange eyes, white skin, one eye = 1:1:1:1:1:1:1:1.
So, in view of above option B is most appropriate.
Note: In a trihybrid cross, a total of 64 progeny types may be produced.
