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Tom [10]
3 years ago
11

Sandra has only Re 1 and Rs 2 coins with her. If the total number of coins that she has is 50 and

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
3 0

I hope this helps you. Plz mark me as the brainliest.

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A factory made 900 jars of peanut butter. 35% of the jars contained creamy peanut butter. How many jars of creamy peanut butter
DIA [1.3K]

Answer:

315 jars

Step-by-step explanation:

This question is merely another way of writing: what is 35% of 900?

Now, when we look at it that way, it's easy to solve.

So, the way to solve is to either multiply 35% by 900, or just interpret that as 0.35 times 900. Anyway, the result is 315.

I hope this helped a bunch! Tell me if you need any further assistance...

( :

5 0
2 years ago
Factor completely 3x2 − 11x 8. (x 4)(3x − 2) (x − 2)(3x − 4) (x 1)(3x − 8) (x − 1)(3x − 8).
earnstyle [38]

The factors of the equation 3x^{2} -11x+8 will be (3x-8)(x-1)

<h3>What will be the factors of the given equation?</h3>

When we split the equation into two groups we will get

3x^{2} -3x-8x+8

3x(x-1)-8(x-1)

Now taking (x-1) common

(3x-8)(x-1)

Thus the factors of the equation 3x^{2} -11x+8 will be (3x-8)(x-1)

To know more about the factors of quadratic equation follow

brainly.com/question/1214333

3 0
2 years ago
DISNEY HAS 16 MOVIES THAT ARE ELIGIBLE FOR THE DISNEY VAULT. 62.5% OF THE MOVIES ARE AVAILABLE FOR THE SALE. HOW MANY VAULT MOVI
Norma-Jean [14]
You can buy 26 movies
8 0
3 years ago
4/5(20e - 5q) - 1/9(-27q + - 18e)<br><br>help
Lady bird [3.3K]

Answer: =−q+48.929073 <-- coming frm a calculator lol

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%2By%3D1%7D%20%5Catop%20%7Bx-2y%3D4%7D%7D%20%5Cright.%20%5C%5C%5Clef
brilliants [131]

Answer:

<em>(a) x=2, y=-1</em>

<em>(b)  x=2, y=2</em>

<em>(c)</em> \displaystyle x=\frac{5}{2}, y=\frac{5}{4}

<em>(d) x=-2, y=-7</em>

Step-by-step explanation:

<u>Cramer's Rule</u>

It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.

It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

\displaystyle \left \{ {{ax+by=p} \atop {cx+dy=q}} \right.

We call the determinant of the system

\Delta=\begin{vmatrix}a &b \\c  &d \end{vmatrix}

We also define:

\Delta_x=\begin{vmatrix}p &b \\q  &d \end{vmatrix}

And

\Delta_y=\begin{vmatrix}a &p \\c  &q \end{vmatrix}

The solution for x and y is

\displaystyle x=\frac{\Delta_x}{\Delta}

\displaystyle y=\frac{\Delta_y}{\Delta}

(a) The system to solve is

\displaystyle \left \{ {{x+y=1} \atop {x-2y=4}} \right.

Calculating:

\Delta=\begin{vmatrix}1 &1 \\1  &-2 \end{vmatrix}=-2-1=-3

\Delta_x=\begin{vmatrix}1 &1 \\4  &-2 \end{vmatrix}=-2-4=-6

\Delta_y=\begin{vmatrix}1 &1 \\1  &4 \end{vmatrix}=4-3=3

\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2

\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{3}{-3}=-1

The solution is x=2, y=-1

(b) The system to solve is

\displaystyle \left \{ {{4x-y=6} \atop {x-y=0}} \right.

Calculating:

\Delta=\begin{vmatrix}4 &-1 \\1  &-1 \end{vmatrix}=-4+1=-3

\Delta_x=\begin{vmatrix}6 &-1 \\0  &-1 \end{vmatrix}=-6-0=-6

\Delta_y=\begin{vmatrix}4 &6 \\1  &0 \end{vmatrix}=0-6=-6

\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2

\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-6}{-3}=2

The solution is x=2, y=2

(c) The system to solve is

\displaystyle \left \{ {{-x+2y=0} \atop {x+2y=5}} \right.

Calculating:

\Delta=\begin{vmatrix}-1 &2 \\1  &2 \end{vmatrix}=-2-2=-4

\Delta_x=\begin{vmatrix}0 &2 \\5  &2 \end{vmatrix}=0-10=-10

\Delta_y=\begin{vmatrix}-1 &0 \\1  &5 \end{vmatrix}=-5-0=-5

\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-10}{-4}=\frac{5}{2}

\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-5}{-4}=\frac{5}{4}

The solution is

\displaystyle x=\frac{5}{2}, y=\frac{5}{4}

(d) The system to solve is

\displaystyle \left \{ {{6x-y=-5} \atop {4x-2y=6}} \right.

Calculating:

\Delta=\begin{vmatrix}6 &-1 \\4  &-2 \end{vmatrix}=-12+4=-8

\Delta_x=\begin{vmatrix}-5 &-1 \\6  &-2 \end{vmatrix}=10+6=16

\Delta_y=\begin{vmatrix}6 &-5 \\4  &6 \end{vmatrix}=36+20=56

\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{16}{-8}=-2

\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{56}{-8}=-7

The solution is x=-2, y=-7

4 0
3 years ago
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