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3 years ago

Which graph correctly solves the system of equations below?

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

8 0

(0,7) (-1,5)
these are the point of intersections

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Which set of numbers represents a Pythagorean triple

Anuta_ua [19.1K]

Answer:

27,36,45

Step-by-step explanation:

Pythagorean theorem

$a^{2} +b^{2} =c^{2}$

$6^{2}+ 9^{2}\\ =117\\\neq 12^{2}$

$7^{2}+ 10^{2}\\ =149\\\neq 12^{2}$

$16^{2}+ 18^{2}\\ =580\\\neq 25^{2}$

$27^{2}+ 36^{2}\\ =2025\\= 45^{2}$

3 0

2 years ago

ASAP!! I need help. -w-Which answer choice shows 5 +0.9 + 0.06 written in standard form?

miss Akunina [59]

The answer is c . 5.96

7 0

3 years ago

Read 2 more answers

PLS HELP IT’S DUE TMR!!

ValentinkaMS [17]

Answer:

Use ≈ (approximately equal) sign as the scientific notation.

Step-by-step explanation:

(a) 0.001872 ≈ 0.0019

(b) 0.3411 ≈ 0.34

*Zeros before non-zero numbers are not significant.

*Zeros appearing between two non-zero digits are significant.

Hope this helps!!

6 0

2 years ago

Use the accompanying table of standard scores and their percentiles under the normal distribution to find the approximate standa

olganol [36]

Answer:

option a

Step-by-step explanation:

markme brainliest

3 0

3 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

2 years ago