Eeeeeeeeeeee help me :C
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<u>Given</u>:
Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).
We need to determine the coordinates of the image after a reflection over the x - axis.
Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.
<u>Coordinates of the point A':</u>
The general rule to reflect the coordinate across the x - axis is given by
Substituting the point A(-2,3), we get;
Thus, the coordinates of the point A' is (-2,-3)
<u>Coordinates of the point B':</u>
The general rule to reflect the coordinate across the x - axis is given by
Substituting the point B(0,3), we get;
Thus, the coordinates of the point B' is (0,-3)
<u>Coordinates of the point C':</u>
The general rule to reflect the coordinate across the x - axis is given by
Substituting the point C(-1,-1), we get;
Thus, the coordinates of the point C' is (-1,1)
Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)
For the units positions of all numbers we have:
From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:
For the tens positions of all numbers we have:
The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.
Now we insert x and z to find out y:
Now we need to find out the product of these three numbers:
From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:
For the tens positions of all numbers we have:
The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.
Now we insert x and z to find out y:
Now we need to find out the product of these three numbers: