X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
y=-
x+3
Step-by-step explanation:
Answer:
11/8 and 21/16
Step-by-step explanation:
3 x 1 = 3
4 x 2= 8
3/8+3/4(convert to eighth's)
3/8+6/8=11/8
1 1/8 = 9/8
9 x 1 = 9
8 x 2 = 16
9/16+3/4(convert to sixteenth's)
9/16+12/16
21/16
---
hope it helps
Answer: 
Step-by-step explanation:
