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navik [9.2K]
3 years ago
12

How do I do number three help pleaseeeeeeee

Mathematics
1 answer:
posledela3 years ago
4 0
I got 36. I did 5-2=3, 3•180=540, 540/5=108, 180-108=72, and 72/2= 36
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Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
What is the perimeter of a polygon with the vertices at (-2,1) (-2,4) (2,7) (6,4) (6,1)?
rusak2 [61]

Answer:

24

Step-by-step explanation:

3 0
3 years ago
Find the mean of the data set: 8, 6, 4.
White raven [17]
Mean = Sum / number

Mean = (8 + 6 +4) / 3

           =  18 / 3

           = 6

Mean = 6
3 0
3 years ago
Read 2 more answers
JUST ANSWER NUMBER 10
jeka57 [31]

Answer:

answer is (14x+6) hope it helps

4 0
2 years ago
Read 2 more answers
If a projectile is launched vertically upward from 800 ft above the ground with an initial velocity of 80 ft per second, its hei
tiny-mole [99]

Hello!

10 seconds to return to the ground.

7 seconds to reach 576 feet above the ground.

Find the amount of time taken to reach the ground by setting the equation equal to 0:

0 = -16t² + 80t + 800

Factor out -16 from the equation:

0 = -16(t² - 5t - 50)

Factor the terms inside of the parenthesis:

0 = -16(t - 10)(t + 5)

Find the zeros:

t - 10 = 0

t = 10

t + 5 = 0

t = -5

Time can only be positive in this instance, so the correct answer is 10 sec.

Find the time by substituting in 576 for the height:

576 = -16t² + 80t + 800

Subtract 800 from both sides:

-224 = -16t² + 80t

Rearrange:

0 = -16t² + 80t + 224

Simplify:

0 = -16(t² - 5t - 14)

0 = -16(t - 7)(t + 2)

t = 7 seconds.

8 0
3 years ago
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