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3 years ago

Which could be the missing data item for the given set of data if the median of the complete data set is 50?

Mathematics

2 answers:

gogolik [260]3 years ago

5 0

Answer:

Find the median of this data

21+23+60+60+50+54+54+59+26+15+43+15=480/ 12 = 40

Now the median should be 50 so take 50 - 40 = 10

The missing number from the data is 10

qwelly [4]3 years ago

3 0

Answer: Correct me if i'm wrong, but I think the closest answer would be 45.

Step-by-step explanation:

Arrange data values from lowest to highest value

The median is the data value in the middle of the set

If there are 2 data values in the middle the median is the mean of those 2 values.

If you need help, try and use this website: https://www.calculatorsoup.com/calculators/statistics/mean-median-mode.php (It has worked in the past for me.)

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Kipton puts one marshmallow on the scale and it weighs 7.2 grams. How much would 10 marshmallows weigh?

Maksim231197 [3]

Answer:

72 grams

Step-by-step explanation:

7.2 x 10 = 72

7 0

3 years ago

Solve for y when x = 2. y = 4x +2 * I REALLY NEED HELP HHDJDICUHDHHEI HELP ME BRUH

Oksi-84 [34.3K]

Answer:

y=10

Step-by-step explanation:

y=4x+2

y=4(2)+2

y=8+2

y=10

8 0

3 years ago

Read 2 more answers

Water pours into a tank at the rate of 2000 cm3/min. The tank is cylindrical with radius 2 meters. How fast is the height of wat

Gennadij [26K]

Volume of water in the tank:

$V=\pi (2\,\mathrm m)^2h=\pi(200\,\mathrm{cm})^2h$

Differentiate both sides with respect to time t :

$\dfrac{\mathrm dV}{\mathrm dt}=\pi(200\,\mathrm{cm})^2\dfrac{\mathrm dh}{\mathrm dt}$

V changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for dh/dt :

$2000\dfrac{\mathrm{cm}^3}{\rm min}=\pi(40,000\,\mathrm{cm}^2)\dfrac{\mathrm dh}{\mathrm dt}$

$\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{2000}{40,000\pi}\dfrac{\rm cm}{\rm min}=\dfrac1{20\pi}\dfrac{\rm cm}{\rm min}$

(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)

7 0

3 years ago

Find the quotient. x + 7 x ÷ 9 x

kicyunya [14]

The first step for solving this expression is to write the division as a fraction.
x + $\frac{7x}{9}$ × x
Calculate the product.
$\frac{7x X x}{9}$
Remember that if a term doesn't have an exponent,, it is considered that the exponent for that term is 1. This changes the expression to the following:
$\frac{7 x^{1}X x^{1} }{9}$
Now multiply the terms with the same base by adding their exponents.
$\frac{7 x^{1+1}}{9}$
Finally,, add the numbers together to get your final answer.
x + $\frac{7 x^{2}}{9}$
Let me know if you have any further questions.
:)

8 0

3 years ago

Which is an equation of the line that contains the points (0,2) (4,0)

alekssr [168]

Answer:

Y= -1/2x+2

Step-by-step explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (0,2), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=0 and y1=2.

Also, let's call the second point you gave, (4,0), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=4 and y2=0.

Now, just plug the numbers into the formula for m above, like this:

0 - 2

4 - 0

or...

-2

or...

m=-1/2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-1/2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(0,2). When x of the line is 0, y of the line must be 2.

(4,0). When x of the line is 4, y of the line must be 0.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-1/2x+b. b is what we want, the -1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (0,2) and (4,0).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(0,2). y=mx+b or 2=-1/2 × 0+b, or solving for b: b=2-(-1/2)(0). b=2.

(4,0). y=mx+b or 0=-1/2 × 4+b, or solving for b: b=0-(-1/2)(4). b=2.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(0,2) and (4,0)

y=-1/2x+2

4 0

3 years ago