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Crank
3 years ago
14

How can i use scalling to help predict the product of a number anda fraction

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0
You could .......... lol wth am I talking about wanna go out 4 lunch girl
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Please help me asap have a great day
GREYUIT [131]

Answer:

C, 15

Step-by-step explanation:

i looked it up

5 0
3 years ago
Need help on the last question
Ray Of Light [21]

Answer: no thank you

Step-by-step explanation:

For 5 free points

7 0
2 years ago
David has a triangular prism that has an equilateral base. Also, the base of the prism is of the same length as its height. Pick
Komok [63]

Answer:

a) Triangle

b) Rectangle

Step-by-step explanation:

A triangular prism that has an equilateral base and a height with the same length as the base of the prism.

a) Shape from horizontal slicing

A plane parallel to the base of a triangular prism will  intersect a cross section that is the same shape as its  bases. So the cross section of the horizontal slicing is an equilateral triangle (all the sides of the triangle are equal).

b) Shape from vertical slicing

If the triangular prism is sliced vertically, the resulting shape would be a rectangle with a length that is the same as the base of the prism.

4 0
3 years ago
What does exlamitory mean
Pachacha [2.7K]

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6 0
3 years ago
Find the price-demand equation for a particular brand television when the demand is 20 TVs per week at $150 per TV, given that t
Alina [70]

Answer:

~150=50e^{-0.01()20}

~p(100)=\$127.7

Step-by-step explanation:

From the question we are told that:

Price of 20TVs per week P_{20}=\$150

Marginal price-demand function p'(x)=-0.5e-0.01x

Generally the The Marginal price function is mathematically given by

  p'(x)=-0.5e^{-0.01x}  

  p(x)=\int-0.5e^{-0.01x}  

  p(x)=50e^{-0.001x}+C  

Therefore the equation when the demand is 20 TVs per week at $150 per TV

150=50e^{-0.01()20}

Giving

p(x)=50e^{-0.01x}+150-50e^{-0.01(20)}

Therefore the Price when the demand is 100 TVs per week

p(100)=50e^{-0.01(100)}+150-50e^{-0.01(20)}

p(100)=\$127.7

7 0
2 years ago
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