The formula to find the volume of a cylinder is v= hㅠr*2, so you can sub the measurements into the formula.
V = (6)ㅠ(2)*2
V = 6ㅠ4
V= 75.4 (approx)
Answer:
m∠RQS = 72°
m∠TQS = 83°
Step-by-step explanation:
m∠RQS +m ∠TQS = m∠RQT
The two angles combine to make a larger angle
So
m∠RQS = (4x - 20)
m∠TQS = (3x + 14)
(4x - 20) + (3x + 14) = 155
Group the Xs and the constants
4x + 3x - 20 + 14 = 155
Combine like terms
7x - 6 = 155
Add 6 to both sides
7x = 161
Divide by 7 on both sides
x = 23
Check:
4(23) - 20 + 3(23) + 14 = 155
92 - 20 + 69 + 14 = 155
155 = 155
But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.
m∠RQS = 4(23) - 20 = 72°
m∠TQS = 3(23) + 14 = 83°
Checking:
72 + 83 = 155
Answer:
(5.4582 ; 6.8618)
Step-by-step explanation:
Given the data:
6 10 2 6 3 3 3 6 6 6 6 5 8 9 10 10 7 9 3 6 5 10 9 9 10 3 8 6 6 3 3 6 6 5 4 10 9 3 5 7 10 6 3 8 6 8 3 3 5 5
Sample mean, xbar = Σx / n
n = sample size = 50
ΣX = 308
xbar = 308 / 50 = 6.16
Using a Calculator :
The sample standard deviation, s = 2.469
Confidence interval = xbar ± margin of error
Margin of Error = Tcritical * s/sqrt(n)
Tcritical at 95% ; df = 50 - 1 = 49
Tcritical = 2.010
Hence,
Margin of Error= 2.010 * (2.469/sqrt(50)) = 0.7018
Lower boundary : (6.16 - 0.7018) = 5.4582
Upper boundary : (6.16 + 0.7018) = 6.8618
(5.4582 ; 6.8618)
Answer:
p=405+60logx
from 2024 to 2010
=14years
p=405+60log14
p=405+60×1.15
p=405+69
p=474
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