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victus00 [196]
3 years ago
11

Which of the following statements are true?

Mathematics
1 answer:
Fantom [35]3 years ago
8 0

Answer:

option A and B are correct.

Step-by-step explanation:

Given: p(t) = \frac{64}{1 + 11e^{-.08t} }

Option A: \lim_{t \to \infty} \frac{64}{1 + 11e^{-.08(\infty)} }  = \frac{64}{1 + 0}  = 64

Option A is true,

Option B: P(0) = \frac{64}{1 + 11}  = 5.33

Option B is also true.

Option C:

P(t + 1) = \frac{64}{1 + 11e^{-.08(t + 1)} }  = \frac{64}{1 + 10.15e^{-.08t} } \\1.08 · P(t) = \frac{64 · 1.08 }{1 + 11e^{-.08t} }   = \frac{69.12}{1 + 11e^{-.08t} }

P(t + 1) ≠ 1.08 · P(t)

Option C is incorrect.

Option D:  It is also incorrect, because according to option 2 earth's population will not grow exponentially without Bound.

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8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member
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Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

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Step-by-step explanation:

Given : The total number of students in the council = 30

The number of students needed to be chosen = 5

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So we Combinations (If order matters then we use permutations.)

The number of combinations of to select r things of n things = ^nC_r=\dfrac{n!}{r!(n-r)!}

So the number of ways a committee of 5 students can be chosen from a student council of 30 students=^{30}C_5=\dfrac{30!}{5!(30-5)!}

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Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

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