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ololo11 [35]
3 years ago
8

Help please I’m stuck

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0

Answer:

10.5

Step-by-step explanation:

ΔXYZ is similar to ΔABC.  So the corresponding sides are proportional:

XY / AB = XZ / AC = YZ / BC

We want to find length AB, so we can either use the first proportion:

7 / k = 3 / 4.5

Or we can use the second proportion:

7 / k = 6 / 9

Either way, we'll get the same answer.  I'll use the second proportion.  Cross multiplying:

6k = 63

Dividing:

k = 10.5

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Me. Silvera bought a can of paint. He used 3/8 of it to paint a fence and 1/4 to paint a table top. He painted a chair with some
LuckyWell [14K]
Well, seeing the information above, he used 5/8 of paint to paint the fence and table top. If he only had 1/8 left of the paint, he used 2/8 on the chair.

I found the 5/8 because I needed a common denominator. I multiplied the top and bottom by 2 to get 2/8. 3/8+2/8=5/8, and then I added 2/8 to the 5/8 that then gave me 7/8 of paint used, and 1/8 of paint left. 

Hope I helped!
3 0
4 years ago
Which shows the most reasonable way to estimate 3 and StartFraction 4 over 7 EndFraction (Negative 2 and StartFraction 1 over 12
geniusboy [140]

Answer:

it's b

Step-by-step explanation:

7 0
2 years ago
if trapezoid ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A’lie
maria [59]

Answer:

<em>Answer: (second option) (-4,1)</em>

Step-by-step explanation:

<u>Transformations of Points and Shapes</u>

The image shows a trapezoid ABCD where point A has coordinates (-4,1).

The following transformations are performed:

Reflection over the y-axis: If a point (x,y) is reflected over the y-axis, it becomes (-x,y). Thus point A becomes A'=(4,1)

Reflection over the x-axis: If a point (x,y) is reflected over the x-axis, it becomes (x,-y). Thus point A' becomes A''=(4,-1)

Rotation 180°: If a point (x,y) is rotated 180°, it becomes (-x,-y). Thus point A'' becomes A'''=(-4,1)

Answer: (second option) (-4,1)

5 0
3 years ago
Which point is in the solution set of the given system of inequalities 3x+y&gt;-3,x+2y&lt;4
Dima020 [189]
Step 1. Solve both inequalities for y:
3x+y\ \textgreater \ -3
y\ \textgreater \ -3x-3

x+2y\ \textless \ 4
2y\ \textless \ -x+4
y\ \textless \ - \frac{1}{2} x+2

Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines -3x-3 and - \frac{1}{2} x+2:

y=-3x-3 (1)
y=- \frac{1}{2} x+2 (2)

Replace (1) in (2):
-3x-3=- \frac{1}{2} x+2
Solve for x:
\frac{5}{2} x=-5
x=-2 (3)

Replace (3) in (1):
y=-3x-3
y=-3(-2)-3
y=6-3
y=3

We can conclude that the point (-2,3) is in the solution of the system if <span>inequalities</span>; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.

4 0
3 years ago
Read 2 more answers
What is the equation of a line that passes through (-6, 2) and has a slope of `-(1)/(2)` ?
o-na [289]
This answer would be d
8 0
3 years ago
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