Let 2x – y = 3 ——— equation 1
Let x + 5y = 14 ——— equation 2
Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3
• Put eqn 3 in eqn 2
(y + 3 / 2) + 5y = 14
6y = 14 – 3/2
6y = 25/2
y = 25/12
• put y = 25/12 in eqn 3
x = (25/12 + 3/2)
x = 43/12
4.4a-7.3 is equal to
4.4a= 7.3 divide both sides by 4.4
a= 1.66
Using the Pythagorean Theorem, we have x^2+(x+2)^2=51^2, and
x^2+ x^2+4x+4=2x^2+4x+4=51^2. After that, we subtract 51^2 from both sides to get 2x^2+4x-2597. Using the quadratic formula (x=(-b+-sqrt(b^2-4ac))/2a in ax^2+bx+c), we get around 35 for x. We did + instead of minus after b due to that it can't be negative! x+2=37, so you save 35+37-51=around 21 feet
