Answer:
<h2>1. x - 2y = -6</h2><h2>2. x + 3y = 0</h2>
Step-by-step explanation:
The Standard form of an eqaution of a line:
![Ax+By=C](https://tex.z-dn.net/?f=Ax%2BBy%3DC)
<h2>1.</h2>
<em>multiply both sides by 2</em>
![2y=2\!\!\!\!\diagup^1\cdot\dfrac{1}{2\!\!\!\!\diagup_1}x+(2)(3)](https://tex.z-dn.net/?f=2y%3D2%5C%21%5C%21%5C%21%5C%21%5Cdiagup%5E1%5Ccdot%5Cdfrac%7B1%7D%7B2%5C%21%5C%21%5C%21%5C%21%5Cdiagup_1%7Dx%2B%282%29%283%29)
<em>subtract </em><em>x</em><em> from both sides</em>
![-x+2y=x-x+6](https://tex.z-dn.net/?f=-x%2B2y%3Dx-x%2B6)
<em>change the signs</em>
![x-2y=-6](https://tex.z-dn.net/?f=x-2y%3D-6)
<h2>2.</h2>
<em>multiply both sides by 3</em>
![3y-(3)(2)=3\!\!\!\!\diagup^1\cdot\left(-\dfrac{1}{3\!\!\!\!\diagup_1}\right)(x+6)](https://tex.z-dn.net/?f=3y-%283%29%282%29%3D3%5C%21%5C%21%5C%21%5C%21%5Cdiagup%5E1%5Ccdot%5Cleft%28-%5Cdfrac%7B1%7D%7B3%5C%21%5C%21%5C%21%5C%21%5Cdiagup_1%7D%5Cright%29%28x%2B6%29)
![3y-6=-(x+6)](https://tex.z-dn.net/?f=3y-6%3D-%28x%2B6%29)
<em>add 6 to both sides</em>
![3y-6+6=-x-6+6](https://tex.z-dn.net/?f=3y-6%2B6%3D-x-6%2B6)
<em>add </em><em>x</em><em> to both sides</em>
![x+3y=-x+x](https://tex.z-dn.net/?f=x%2B3y%3D-x%2Bx)
![x+3y=0](https://tex.z-dn.net/?f=x%2B3y%3D0)