You mix the letters m,a,t,h,e,m,a,t,i,c,a and l thoroughly without looking you draw one letter probability p(A) . write the prob
erastovalidia [21]
There are 12 total letters, of which 3 are A's.
This means you have a
probability of randomly selecting an A.
Let's use the variable "r" to represent the investment rate of the stocks:
2r(500) + r(800) = 45
1000r + 800r = 45
1800r = 45
r = 0.025
2r = 0.05
The $500 is invested at 5%
Answer:
Vertical angle=9.5°
Time to reach maximum height = 1.24seconds
Step-by-step explanation:
The maximum distance x is reached when rope swings to a maximum height, maximum height is gotten from the equation KE= 1/2MU^2 = MgH = MgL= Mgl(1- cos theta.
Where theta is the vertical angle, U=2m/s and L= 15m
2gl -2glcostheta=U^2
2gl U^2=2gl cos theta
But theta= Acos(1- U^2)/2gl
Acos(1-/(2×9.8×15)
Theta =9.5°
Maximum height li given by
Lsintheta
But X= UxT
T=X/UX= Lsintheta/U = 15sin9.5 /2 =1.24seconds
Answer:
(A) T-stat = 1.82
(B) Critical value is 1.645
(C) Yes, there is sufficient evidence to reject the null hypothesis using a 0.05 significance level.
Step-by-step explanation:
(A) T-stat (z) = (sample mean - population mean) ÷ sd/√n
sample mean = 3850 bus miles
population mean = 3800 bus miles
sd = 275 bus miles
n = 100
z = (3850 - 3800) ÷ 275/√100 = 50 ÷ 275/10 = 50 ÷ 27.5 = 1.82
(B) The test is a one-tailed test. The critical value is obtained from the standard normal distribution table. The critical value using a 0.05 significance level is 1.645
(C) Null hypothesis: The bus mechanical reliability is 3850 bus miles.
Alternate hypothesis: The bus mechanical reliability is less than 3850 bus miles.
Conclusion:
There is sufficient evidence to reject the null hypothesis because the test statistic (1.82) is greater than the critical value (1.645)
