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drek231 [11]
3 years ago
10

Simplify the expression please

Mathematics
1 answer:
Reika [66]3 years ago
3 0
\bf -2(3+2i)+2(4-5i)\implies 
\\\\\\
-6+8-10i-4i\implies \boxed{2-14i}
You might be interested in
I need help ASAP <br><br><br> -2x^2+x<br><br> 9-25x^2+8x<br><br> X^5+x^3-x^2-1
nika2105 [10]

Answer:

For -2x^2+x, Leading coefficient is -2, Degree is 2, Constant term is 0

For 9-25x^2+8x, Leading coefficient is -25, Degree is 2, Constant term is 9

For x^5+x^3-x^2-1, Leading coefficient is 1, Degree is 5, Constant term is -1

Step-by-step explanation:

Given:

Polynomials:

-2x^2+x\\9-25x^2+8x\\x^5+x^3-x^2-1

To find: leading coefficient, constant term and degree

Solution:

Leading coefficient is the coefficient of the variable with the highest power.

Degree is the highest power of the variable.

The term of degree 0 is the constant term of a polynomial.

For -2x^2+x,

Leading coefficient is -2

Degree is 2

Constant term is 0

For 9-25x^2+8x

Leading coefficient is -25

Degree is 2

Constant term is 9

For x^5+x^3-x^2-1

Leading coefficient is 1

Degree is 5

Constant term is -1

4 0
3 years ago
Please help me ......:(
algol [13]

Answer:  B) F(x) = √x and G(x) = 3x + 2

<u>Step-by-step explanation:</u>

The composite function G(F(x)) is when you replace every x-value in the G(x) function with the F(x) function.

A)\ G(3x+2) = \sqrt{3x+2}\\\\B)\ G(\sqrt{x})=3(\sqrt{x})+2\quad =3\sqrt{x}+2\\\\C)\ G(\sqrt{x}+2) = 3\quad \text{there are no x-values in the G(x) function to replace}\\\\D) G(3\sqrt{x})=2\quad \text{there are no x-values in the G(x) function to replace}

The only one that matches G(F(x)) = 3√x + 2 is OPTION B

5 0
3 years ago
10. Write the ratio as a fraction in simplest form.<br> 12 : 42
Pavel [41]

Answer:

2/7

Step-by-step explanation:

12 : 42 is the same as 12/42

simplify the fraction by dividing the numerator and denominator by 6

you get 2/7

8 0
3 years ago
Read 2 more answers
2(h - 8) - h = h - 16
tresset_1 [31]

2(h-8)-h=h-16

2h-16-h=h-16

h=h

h has infinitely many solutions.

5 0
2 years ago
Three circles with centers A, B, and C are externally tangent to each other as shown in the figure. Lines EG and DG are tangent
fiasKO [112]
My solution to the problem is as follows:

EC = 15 ... draw CF = 6 (radius) ...use Pythagorean theorem to find EF. 

EF^2 + CF^2 = EC^2 
EF^2 = 15^2 - 6^2 = 189 .... EF = sq root 189 

triangle GDE is similar to CFE ... thus proportional 
GD / ED = CF / EF 
GD / 18 = 6 / (sq root 189) 
<span>GD = 108 / (sq root 189)

I hope my answer has come to your help. God bless and have a nice day ahead!


</span>
5 0
3 years ago
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