Answer:
<em>Factored Form: </em><em> </em><em>( y - 2 )( 3y + 7 )</em>
Step-by-step explanation:
<em>1. Let us first write down the problem at hand: </em>3y^2 + y - 14
<em>2. Now let us break this expression into groups: </em>
3y^2 - 6y + 7y - 14 ⇒ ( 3y^2 - 6y )( 7y - 14 )
<em>3. Factor 3y from 3y^2 - 6y:</em>
3y^2 - 6y ⇒ 3y( y - 2 )
<em>4. Factor 7 from 7y - 14:</em>
7y - 14 ⇒ 7( y - 2 )
<em>5. Substitute Step #3, 4 ⇒ Step #2:</em>
3y( y - 2 ) + 7( y - 2 )
<em>6. Factor common term y - 2:</em>
<em>Answer: ( y - 2 )( 3y + 7 )</em>
Answer: 130
In order to solve for <4, you need to know that supplementary angles add up to 180°.
<3 = 50
180 - 50
130
**For future questions**
1. The sum of the interior angles of a triangle is 180°
2. Alternate interior angles are congruent
3. The exterior angle of a triangle is the sum of the nonadjacent interior angles
See attachment below.
Answer:
x= 24 and y = 6
Step-by-step explanation:
I think that the right answer
Answer:
20
Step-by-step explanation:
Since we have given that
Dimensions of a triangle he has to use for fencing are
15 feet, 8 feet, and 20 feet.
1) For making it a right triangle it must satisfy the "Pythagoras theorem" which states that



No, it will not be able to make a right triangle.
2) Joel cut the longest piece of wood in order to make a right triangle.
So, from above we get that
So, the longest side must be 17 feet.
It takes him 30 seconds to install each foot of fencing,
The total perimeter of fencing will be
17 + 15 + 8 = 40 feet
So, for 1 foot he needs = 30 seconds
For 40 feet, he will need
40 × 30 = 1,200 seconds
1200/600 = 20 minutes
Hence, he needs 20 minutes to install all of the fences.
<h3>
<u>Answer:</u></h3>

<h3>
<u>Step-by-step explanation:</u></h3>
Given that , One number is 1 more than 7 times the other number. If their sum is 73 more than
twice the smaller number. And we need to find the numbers. So let us take the
- First Number be x .
- Second number be 7x+1 .

Hence the smaller number is 12 and the bigger number will be :-
<h3>
<u>Hence </u><u>the</u><u> </u><u>bigger </u><u>number</u><u> </u><u>is</u><u> </u><u>8</u><u>5</u><u> </u><u>and</u><u> </u><u>the </u><u>small</u><u>er</u><u> number</u><u> </u><u>is</u><u> </u><u>1</u><u>2</u><u>. </u></h3>