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sineoko [7]
3 years ago
7

(N^16) 1/4 Need help

Mathematics
2 answers:
Shtirlitz [24]3 years ago
6 0

Answer:

{n}^{16} \times 1  \div 4 \\   {n}^{4}

Step-by-step explanation:

4 times 4 is 16 so while both are in power so we can do this like that

Mama L [17]3 years ago
3 0

For this case we have the following expression:

(N^{16}) ^ {\frac {1} {4}}

By definition of power properties we have:

(a ^ n) ^ m = a ^ {n * m}

So, rewriting the expression we have:

N ^ {\frac {16 * 1} {4}} =\\N ^ {\frac {16} {4}} =\\N ^ 4

Thus, the expression is reduced to N ^ 4

Answer:

N ^ 4

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9999*886+234

(9999*886)+234

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Answer:

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Step-by-step explanation:

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Find the difference between 8/10 and -2 Show all calculations in your final answer.
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What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

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2 years ago
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