<h2>Given :-</h2>
In □PQRS side PQ∥ side RS. If m∠P = 108degree
and m∠R = 53degree
<h2>To Find :-</h2>
m∠Q and m∠S.
<h2>Solution :-</h2>
According to angle sum property
P∠Q=180−∠P
∠Q=180−108

For angle S
∠S=180−∠R
∠S=180−53


<h3>
Therefore the area of remaining board =13.76 square feet</h3>
Step-by-step explanation:
Given , The length of side of the square is 8 feet.
Since a circle is inscribed in the square. Then the diameter of the circle is equal to the length of side of the square .
Therefore the diameter of the circle is = 8 feet.
Radius of the circle is(r) =
feet = 4 feet
The area of the circle is= 3.14 r²
= 3.14 × 4² square feet
= 50.24 square feet
The area of the square is = side × side
= 8×6 square feet
=64 square feet
Therefore the area of remaining board = (64- 50.24)square feet
=13.76 square feet
(2X-3)(4-3X)
=8X-6X²-12+9X
=-6X²+17X-12
That's your answer.
The linear equation y = -6x + 2; -12x - 2y = -4 has no solution
<h3>Linear equation</h3>
y = -6x + 2
-12x - 2y = -4
- Substitute y = -6x + 2 into (2)
-12x - 2y = -4
-12x - 2(-6x + 2) = -4
-12x + 12x -4 = -4
-12x + 12x = - 4 + 4
0 = 0
y = -6x + 2
y - 2 = -6x
x = (y - 2) / -6
-12x - 2y = -4
-12(y- 2)/ 6 - 2y = -4
(-12y + 24) / 6 - 2y = -4
-2y + 4 - 2y = 4
0 = 0
Learn more about linear equation:
brainly.com/question/4074386
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