Find a vector of magnitude 3 in the direction of v = 10i - 24k. The vector is Oi-Oj+k (Simplify your answer. Use integers or fra
ctions for any numbers in the expression).
1 answer:
Given :
A vector v = 10i - 24k.
To Find :
A vector of magnitude 3 in the direction of v = 10i - 24k.
Solution :
Unit vector in the direction of vector v is :

Now , vector of magnitude 3 in direction v is :

Hence , this is the required solution .
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In my opinion the answer is <span>m2 – 100 = –99
proof
</span>m2 – 100 =<span>(m – 10)(m + 10)
for eg. m=1, </span>(-9)(11)= <span>–99</span>
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140m
Step-by-step explanation:
3/4 = .75
x/.7 = 150/.75
multiply both sides by .7
x = 150/.75 * .7
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