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3 years ago

12. How many hours pass by if

Mathematics

2 answers:

Nana76 [90]3 years ago

5 0

The answer to this question is 1 hour.

zmey [24]3 years ago

4 0

1 hour. it only went around once

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A spool of rope contains 79 yards of rope. How many 4-foot pieces of rope can be cut from the spool? How much rope is left ov

mart [117]

<h2>Answer:</h2>

59 can be cut from the spool.

3 Inches is left over.

<h2>Step-by-step explanation:</h2>

237 feet in 79 yards.
237 / 4 = 59.25
59 is the whole number, .25 is what is left over.
.25 feet is 3 inches.

8 0

3 years ago

Read 2 more answers

A certain drug treatment cures 90% of cases of hookworm in children.18 Suppose that 20 children suffer- ing from hookworm are to

Anni [7]

Answer:

Step-by-step explanation:

Here X the no of children suffering from hookworm treated and recovered is binomial because

a) Each child is independent of the other

b) There are only two outcomes

c) The probability for any child to recover is constant as 90% = 0.9

X is Bin (20,0.9)

a) Prob that all 20 will be cured

=P(X=20)= $0.9^{20} \\=0.1216$

b) Prob all but 1 will be cured= $P(x=1) = 20C1 (0.9) (.1)^{19} \\=1.8(10^8)$

c) Prob exactly 18 will be cured

$=P(X=18)\\=20C18 (0.9)^{18} (0.1)^2\\= 0.2852$

d) Prob exactly 90% will be cured.

= $P(X=18)\\=20C18 (0.9)^{18} (0.1)^2\\= 0.2852$

7 0

4 years ago

use a graphing calculator or other technology to answer the question which quadratic regression equation best fits the data set

Greeley [361]

Answer:

Option C is the correct option.

In other words, the quadratic regression $y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:$ best fits the data set, as it gets very much close to the data values given in the data table.

The graph of the equation $y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:$ is also attached.

Step-by-step explanation:

x y

3 470

4 416

5 403

Analyzing Option A:

Considering the equation

$y=32.86\:\left(x\right)^2+379.14\left(x\right)-1369.14\:$

From (3, 470), putting x = 3

$y=32.86\:\left(3\right)^2+379.14\left(3\right)-1369.14\:$

$y=64.02$

From (4, 470), putting x = 4

$y=32.86\:\left(4\right)^2+379.14\left(4\right)-1369.14\:\:$

$y=673.18$

From (5, 403), putting x = 5

$y=32.86\:\left(5\right)^2+379.14\left(5\right)-1369.14\:$

$y=1348.06$

Analyzing Option B:

$y=32.86\:\left(x\right)^2-379.14\left(x\right)$

From (3, 470), putting x = 3

$y=32.86\:\left(3\right)^2-379.14\left(3\right)$

$y=-841.68$

From (4, 470), putting x = 4

$y=32.86\:\left(4\right)^2-379.14\left(4\right)$

$\:y=-990.8$

From (5, 403), putting x = 5

$y=32.86\:\left(5\right)^2-379.14\left(5\right)$

$\:y=-1074.2$

Analyzing Option C:

Considering the equation

$y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:$

From (3, 470), putting x = 3

$y=32.86\:\left(3\right)^2-379.14\left(3\right)+1369.14\:$

$y=527.46$

So, the approximately result is (3, 527)

From (4, 470), putting x = 4

$y=32.86\:\left(4\right)^2-379.14\left(4\right)+1369.14\:$

$y=378.34$

So, the approximately result is (4, 378)

From (5, 403), putting x = 5

$y=32.86\:\left(5\right)^2-379.14\left(5\right)+1369.14\:\:\:$

$y=294.94$

So, the approximately result is (5, 295)

Analyzing Option D:

Considering the equation

$y=-1369.14\:\left(x\right)^2-379.14\left(x\right)+32.86$

From (3, 470), putting x = 3

$y=-1369.14\:\left(3\right)^2-379.14\left(3\right)+32.86\:\:$

$y=-13426.82$

From (4, 470), putting x = 4

$y=-1369.14\:\left(4\right)^2-379.14\left(4\right)+32.86$

$y=-23389.94$

From (5, 403), putting x = 5

$y=-1369.14\:\left(5\right)^2-379.14\left(5\right)+32.86\:\:$

$y=-36091.34$

Therefore, from the above calculations and analysis, we conclude that Option C is the correct option.

In other words, the quadratic regression $y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:$ best fits the data set, as it gets very much close to the data values given in the data table.

The graph of the equation $y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:$ is also attached.