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Leviafan [203]
3 years ago
5

What is the unit rate for sukis scrumptious sushi?

Mathematics
2 answers:
Sati [7]3 years ago
7 0
A. 4.50 { 1 sushi roll}
Vladimir [108]3 years ago
5 0
A. 4.50 for 1 sushi roll
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Shankar is teaching 2 courses, let us call them 435 and FYS. 435 has 3 sophomores, 8 juniors and 13 seniors; FYS has 5 sophomore
Mice21 [21]

Answer:

The probability that both students are of the same type is \frac{149}{432}.

Step-by-step explanation:

The students in 435 are: {3 sophomores, 8 juniors and 13 seniors}

Number of students in 435 = 3 + 8 + 13 = 24

The students in FYS are: {5 sophomores, 7 juniors and 6 seniors}.

Number of students in FYS = 5 + 7 + 6 = 18

The teacher picks 1 student from each class.

The probability that both students are of the same type is:

P (Same type students) = P (Both are Sophomores) + P (Both are Juniors)

                                                     + P (Both are Seniors)

= P (Sophomore ∩ Course 435) × P (Sophomore ∩ Course FYS)

         + P (Junior ∩ Course 435) × P (Junior ∩ Course FYS)

               + P (Senior ∩ Course 435) × P (Senior ∩ Course FYS)

                       =[(\frac{3}{24} )\times(\frac{5}{18})]+[(\frac{8}{24} )\times(\frac{7}{18})]+[(\frac{13}{24} )\times(\frac{6}{18})]\\=\frac{15+56+78}{432}\\ =\frac{149}{432}

Thus, the probability that both students are of the same type is \frac{149}{432}.

3 0
3 years ago
What is the area of the circle shown? Use 3.14 for pi.<br> Help me please I need to pass this test
bazaltina [42]
A=3.14r^2
A=3.14 x 10^2
A=3.14x100
A=314
314cm is your answer
7 0
3 years ago
Suppose that P (A)=0.4 AND P (B)=0.2, If events A &amp; B ARE Mutually EXCLUSIVE :
baherus [9]

Part (a) Finding the probability of either A or B

We are told that events A and B are mutually exclusive. This means they cannot happen at the same time. We can say P(A and B) = 0

Furthermore,

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.4 + 0.2 - 0

P(A or B) = 0.6

<h3>Answer:  0.6</h3>

=======================================================

Part (b) Finding the probability of neither A nor B

P(A or B) + P(neither A nor B) = 1

P(neither A nor B) = 1 - P(A or B)

P(neither A nor B) = 1 - 0.6

P(neither A nor B) = 0.4

The reason why this works is to imagine throwing a dart at the Venn diagram. You'll either...

  • you land in A or B (pick one but not both), OR,
  • you'll land outside both regions A and B.

One or the other must happen. Both events cannot happen simultaneously.

<h3>Answer: 0.4</h3>
7 0
3 years ago
ANSWER THIS PLEASE!
Minchanka [31]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
WILL GIVE YOU 50 POINTS
irinina [24]

Answer:

Step-by-step explanation:

8 0
3 years ago
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