Answer:
11/12
Step-by-step explanation:
<h2><u>Value of F </u></h2>
to find the value of f , we need to move the -2/3 to the other side of the equal sign.

<u><em>Note </em></u>: is you move a number from one side of the equal sign to the other, this changes the sign of the number ( eg , -2/3 becomes +2/3)

f = 
<h3><u>hence the value of f is 11/12 </u></h3>
If the vertex is at the maximum point they dy/dx=0 at that point...
dA/dx=-2x+4
dB/dx=-2x+8
dC/dx=2x-4
dD/dx=2x-8
So both B and D have a zero velocity at x=4, but only B is equal to 3 when x=4
B. is the correct quadratic with the vertex at (4,3)
Answer:
31xy
Step-by-step explanation:
28xy + 3xy = 31xy
Answer:
a) Var[z] = 1600
D[z] = 40
b) Var[z] = 2304
D[z] = 48
c) Var[z] = 80
D[z] = 8.94
d) Var[z] = 80
D[z] = 8.94
e) Var[z] = 320
D[z] = 17.88
Step-by-step explanation:
In general
V([x+y] = V[x] + V[y] +2Cov[xy]
how in this problem Cov[XY] = 0, then
V[x+y] = V[x] + V[y]
Also we must use this properti of the variance
V[ax+b] =
V[x]
and remember that
standard desviation = ![\sqrt{Var[x]}](https://tex.z-dn.net/?f=%5Csqrt%7BVar%5Bx%5D%7D)
a) z = 35-10x
Var[z] =
Var[x] = 100*16 = 1600
D[z] =
= 40
b) z = 12x -5
Var[z] =
Var[x] = 144*16 = 2304
D[z] =
= 48
c) z = x + y
Var[z] = Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] =
= 8.94
d) z = x - y
Var[z] = Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] =
= 8.94
e) z = -2x + 2y
Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320
D[z] =
= 17.88