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eduard
3 years ago
8

[20 POINTS] A cylinder has a height of 11 centimeters and its circle bases have a radius of 9 centimeters. Find the surface area

of the cylinder.

Mathematics
1 answer:
galben [10]3 years ago
4 0
The third bubble is correct
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2(4^2+10) ? will mark brainliest
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\bf 2(4^2+10)\qquad \mathbb{PEMDAS}\implies 2(16+10)\implies 2(26)\implies 52
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Solve this problem. 10^3 * 2^3
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10 to the power of 3 would be 1000.
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3 years ago
-3(n+9)=15<br> i need the step of solving this plzz brainliest if right!!
raketka [301]

Answer:

n = -14

Step-by-step explanation:

-3(n+9)=15

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3 years ago
3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

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3 years ago
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Slav-nsk [51]
The denominator is 20

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