Ask question

Ask question

All categories

3 years ago

12

Each class briarwood elementary collect at least 54 of food during the drive. If there are 29 classes in the school,what was the

least number of cans collected

2 answers:

Rashid [163]3 years ago

8 0

Answer: 1566

Step-by-step explanation:

54 x 29 = 1566

julia-pushkina [17]3 years ago

4 0

Answer:

1566

Step-by-step explanation:

20*50=1000

20*4=80

<h3>1000+80=1080</h3>

9*50=450

9*4=36

450+81=486

<h2>1080+486=1566</h2>

You might be interested in

<img src="https://tex.z-dn.net/?f=%20%7B3%7D%5E%7Bx%20%2B%202%7D%20%20-%20%20%7B3%7D%5E%7Bx%7D%20%20%3D%20%20%5Cfrac%7B8%7D%7B9%

ser-zykov [4K]

$3^{x + 2}$ - $3^{x}$ = $3^{x}$ * $3^{2}$ - $3^{x}$ = 9( $3^{x}$ ) - 1( $3^{x}$ ) = 8( $3^{x}$ )

$3^{x + 2}$ - $3^{x}$ = $\frac{8}{9}$

⇒ 8( $3^{x}$ ) = $\frac{8}{9}$

⇒ $3^{x}$ = $\frac{1}{9}$ <em>multiplied both sides by 8</em>

⇒ $3^{x}$ = $\frac{1}{3^{2} }$

⇒ $3^{x}$ = 3⁻²

⇒ x = -2

Answer: x = -2

6 0

3 years ago

an automobile with a mass of 1200 kg accelerates at a rate of 3.0 <img src="https://tex.z-dn.net/?f=m%2Fs%5E%7B2%7D" id="TexForm

r-ruslan [8.4K]

Answer:

3600 N forward

Step-by-step explanation:

Use Newton's second law.

F = ma

F = 1200 kg × 3.0 m/s²

F = 3600 N

4 0

3 years ago

. mrs. opsahl drove 399 miles on 14 gallons of gas. how many miles per gallon did her car get? 0.27 miles per gallon 28.5 miles

Dennis_Churaev [7]

Answer:

28.5 miles per gallon

Step-by-step explanation:

399 miles / 14 gallons

= 28.5 miles/1 gallon

1 gallon per 28.5 miles

8 0

2 years ago

HELP ASAP YES I WILL GIVE BRAINLIEST

olganol [36]

Answer: magnesium >potassium hope it helps

8 0

2 years ago

Read 2 more answers

Z=a/b+c/d solve for A

PilotLPTM [1.2K]

Answer: $a=\frac{b(zd-c)}{d}$

Step-by-step explanation:

Having the following equation given in the exercise:

$z=\frac{a}{b}+\frac{c}{d}$

You can solve for "a" following this procedure:

1. You can apply the Subtraction property of equality and subtract $\frac{c}{d}$ from both sides of the equation:

$z-(\frac{c}{d})=\frac{a}{b}+\frac{c}{d}-(\frac{c}{d})\\\\z-\frac{c}{d}=\frac{a}{b}$

2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:

$\frac{zd-c}{d}=\frac{a}{b}$

3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:

$(b)(\frac{zd-c}{d})=(\frac{a}{b})(b)\\\\a=\frac{b(zd-c)}{d}$

6 0

3 years ago