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3 years ago

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If U = {all positive integers} and A = {x|x ∈ U and x is an odd positive integer}, which describes Ac?

2 answers:

Viefleur [7K]3 years ago

8 0

Im pretty sure its D i might be wrong i havent finished the test yet

tekilochka [14]3 years ago

6 0

The answer is:

D. Ac = {xΙx ∈ U and is an even positive integer}

:)

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3 years ago

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qaws [65]

Answer:

<h2>23.6°</h2>

Step-by-step explanation:

<h3>to understand the solving steps</h3><h3>you need to know about</h3>

trigonometry i.g sin(x)=opp/hypo
PEMDAS

<h3>given:</h3>

opp:6
hypo:15

<h3>to find:</h3>

xyz angle

<h3>let's solve:</h3>

$let \: xyz \: angle \: be \: \alpha$

$according \: to \: the \: question$

$\sin( \alpha ) = \frac{xy}{zy}$

$\sin( \alpha ) = \frac{6}{15}$

$\alpha = asin( \frac{6}{15} )$

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2 years ago