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Ber [7]
4 years ago
12

If U = {all positive integers} and A = {x|x ∈ U and x is an odd positive integer}, which describes Ac?

Mathematics
2 answers:
Viefleur [7K]4 years ago
8 0
Im pretty sure its D i might be wrong i havent finished the test yet
tekilochka [14]4 years ago
6 0
The answer is:


D. Ac = {xΙx ∈ U and is an even positive integer}

:)
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3 0
4 years ago
Determine if the following system of equations has no solutions 4x+3y= -8 -8x-6y= 16
cupoosta [38]

\begin{cases} 4x+3y=-8\\\\ -8x-6y=16 \end{cases}~\hspace{10em} \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

4x+3y=-8\implies 3y=-4x-8\implies y=\cfrac{-4x-8}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3} \\\\[-0.35em] ~\dotfill\\\\ -8x-6y=16\implies -6y=8x+16\implies y=\cfrac{8x+16}{-6} \\\\\\ y=\cfrac{8}{-6}x+\cfrac{16}{-6}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3}

one simple way to tell if both equations do ever meet or have a solution is by checking their slope, notice in this case the slopes are the same for both, meaning the lines are parallel lines, however, notice both equations are really the same, namely the 2nd equation is really the 1st one in disguise.

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3 0
2 years ago
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