Answer:x+2y-12=0
Step-by-step explanation:
3x+6y=36
-36. -36
3x+6y-36=0
Divide by 3 to get
X+2x-12=0
Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by

The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
1.) 2368000 (two million, three hundred sixty-eight thousand)
2.) 864,346,000 rounded to nearest thousand
3.) 864,345,537.00 not 100% on the last answer
Good luck
Answer: Y=-1
Explanation: 2y-3=y-4 (add three on both sides)
2y=y-1 (subtract y on both sides)
y=-1