PLZ HELP!!!!!!!!! AAAAAAAAAAAA
2 answers:
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Answer:
Slide 1:
1. Solution = (-3,2)
<em>y = 2x - 1</em>
<em>y = 3/2x + 6</em>
2. No solution
<em>y = -4/2x + 4</em>
<em>y = -4/2x - 5</em>
Slide 2:
3. Solution = (1, -6) ONE SOLUTION
4. Solution = (-4, -1) ONE SOLUTION
p.s i attached the graphs for problems 3 and 4. The first picture is for problem 3 and the second picture is for problem 4
I really hope this helped :)
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
Solution:
Let f be the bags of flour and b be the pounds of butter.
Cost of 20 bags of flour 16 pound of butter = 110
⇒ 20f + 16b = 110 -------------------- (1)
Cost of 30 bags of flour 12 pound of butter = 120
⇒ 30f + 12b = 120 -------------------- (2)
Equation (1) and (2) are the system of equations.
(2) ⇒ 30f + 12b = 120
Subtract 30f from both sides.
⇒ 12b = 120 – 30f
Divide by 12 on both sides.
-------------------- (3)
Substitute (3) in (1).
Subtract 160 from both sides.
Divide by –20, we get
f = 2.50
Substitute f = 2.5 in equation (3), we get
b = 3.75
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75